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2 years ago

Based on your observations of the six collisions, describe the physical difference between elastic and inelastic collisions.

Physics

1 answer:

Ahat [919]2 years ago

5 0

Answer:

Collisions are basically two types: Elastic, and inelastic collision. Elastic collision is defined as the colliding objects return quickly without undergoing any heat generation. Inelastic collision is defined as the where heat is generated, and colliding objects are distorted.

In elastic collision, the total kinetic energy, momentum are conserved, and there is no wasting of energy occurs. Swinging balls is the good example of elastic collision. In inelastic collision, the energy is not conserved it changes from one form to another for example thermal energy or sound energy. Automobile collision is good example, of inelastic collision.

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Newton’s law of universal gravitation stars that every object in the universe attracts every other object

LenaWriter [7]

Yes it does ! Uh huh. Right you are. Truer words are seldom written.

You have quoted the law quite accurately but also incompletely.

Do you have a question to ask ?

4 0

2 years ago

Why was John Paul Jones's victory important in the war? His victory increased France's confidence in the skill of the Continenta

IRINA_888 [86]

Answer:

C. His victory against a superior British foe inspired the American troops.

Explanation:

John Paul Jones is considered the hero in the Revolutionary War. He is known as the Father of the US Navy.

In the Revolutionary War, Jones sided with the American colonists against the British and took hold of naval ships. In 1779, when the British warship Serapis was in conflict with the American warship Bon Homme Richard, Jones plugged the American warship with the Britisher's warship and tossed a grenade into the opponent warship. Thus when Jones was victorious in the war, this boosted the American spirits for the war.

Therefore, option C is the correct answer.

4 0

2 years ago

Read 2 more answers

An isolated conductor has a net charge of +12.0 × 10- 6 c and a cavity with a particle of charge q = +3.70 × 10-6

pychu [463]

This is just a simple problem finding out the outer surface charge, the inner surface charge and the net charge. Net charge by definition means the difference between two charges. In this case, the formula that is applicable here is outer surface charge = total net charge - inner cavity surface charge. Since we are given already with the net charge equal to 12.0 x10-6 C and the inner charge magnituude f 3.7 x10-6 C, the the total charge must be outer charge is +10x10(-6)) - (-3.0x10(-6)) = +1.3x10(-5) C.
Charges are measured in coloumbs and most likely exist on surfaces of entities like particles, walls etc.

8 0

2 years ago

A circuit has resistors R 1 = 468 Ω and R 2 = 125 Ω R1=468 Ω and R2=125 Ω , and two batteries V 1 = 12.0 V and V 2 = 3.00 V V1=1

Greeley [361]

Answer:

0.0192A

Explanation:

Since, the reading of the galvanometer is 0 A, the voltage across the resistance R will be:

Step 1

VR = V2

VR = 3.00v

Step 2

Calculating the current through the resistance R as below,

IR = V1 - V2 /R1

IR = 12 - 3 /468

IR =0.0192A

7 0

3 years ago

A roller coaster, traveling with an initial speed of 15 meters per second, decelerates uniformly at â7.0 meters per second2 to a

Harrizon [31]

By algebra, d = [(v_f^2) - (v_i^2)]/2a. Thus, d = [(0^2)-(15^2)]/(2*-7) d = [0-(225)]/(-14) d = 225/14 d = 16.0714 m With 2 significant figures in the problem, the car travels 16 meters during deceleration.

8 0

3 years ago