Refer to the diagram shown below.
From the geometry, obtain
x = 2.5 - 0.55 = 1.95 m
cos θ = 1.95/2.5 = 0.78
θ = cos⁻¹ 0.78 = 38.74°
From the free body diagram, the tension in the chain is 450 N.
F is the centripetal force,
W is Dee's weight.
The components of the tension are
Horizontal component = 450 sin(38.74°) = 281.6 N, acting left.
Vertical component = 450 cos(38.74°) = 351.0 N, acting upward.
Answers:
Horizontal: 281.6, acting left.
Vertical: 351.0 N, acting upward.
Answer:
The angular velocity is: (2π radians) ⁄ (4.3 sec) = 1.461 rad/sec
The angular displacement is: (1.461 rad/sec)(1 sec) = 1.461 radians
Explanation:
The correct answer is 0.67 h
The coil's induced emf is specified as e=0. 50 v.
i i = 0.55 A is the initial value of the current flow.
I f = 0.95 A is the total amount of current flowing.
The shift in current occurs in a period of time when dt = 0.40 s.
The self-inductance is determined as follows:
The current change rate is represented here by dI/dt.
Step 2 After entering the values,
As a result, the self-inductance is 0.67 H.
The definition of self inductance is the induction of a voltage in a wire that carries current when the current in the wire is changing. When there is self-inductance, a circuit's own changing current creates a magnetic field that causes a voltage to be induced.
Learn more about Self inductance here :-
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The total resistance of the three resistors connected in series is 1.85Ω.
Explanation:
Whenever a passive device is connected in a circuit, if they are connected parallel to each other, then the voltage drop in each of the passive device will be constant. So in this case, the passive device is the resistor. So three resistors are connected parallel to each other, this means the voltage drop across these three resistors will be constant but the current flow in the three resistors will be different.
So, the net current flow in the circuit will be

From, Ohm's law, we know that 
So, since the voltage drop across the three resistors are same as V, then resistor be denoted as R₁ = 4 Ω R₂ = 6Ω and R₃= 8Ω.
So, the formula becomes,



Thus, the total resistance of the three resistors connected in series is 1.85Ω.