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zysi [14]
3 years ago
15

Chloe charged for admission to her play on three different nights. Each night, a different number of people were in attendance,

but remarkably, Chloe collected $541 each night. If the admission charges for each child and each adult were $9 and $17, respectively, how many people in total came to the three showings?
Mathematics
1 answer:
SpyIntel [72]3 years ago
8 0

Answer:

1st Play 45 people; 2nd Play 37 people; 3rd Play 53 people

Step-by-step explanation:

Admission prices were: $9 per child & $17 per adult.

It is only matter of playing with the numbers until you get the number you want. In this case, the number all plays have in common is $541 which represents the amount she collected for attendance.

1st Play 28 children ($252) + 17 adults ($289) = $541 and 45 people

2nd Play 11 children ($99) + 26 adults ($442) = $541 and 37 people

3rd Play 45 children ($405) + 8 adults ($136) = $541 and 53 people

This way, each night the number of people in attendance was different but the amount collected in each play was $541.

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Please Help me Check the image below!!!!!
WITCHER [35]

Answer:

First question:

The graph of  y=\frac{3-2x}{2-3x} has a vertical asymptote at x =  \frac{2}{3} and a horizontal asymptote at y =  \frac{2}{3}

Second question:

The graph of equation y=\frac{1-3x}{2+x} has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the  denominator is equal to zero

The horizontal asymptotes will occur if:

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First question:

∵ y=\frac{3-2x}{2-3x}

- To find the vertical asymptote equate the denominator by 0

   to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

∴ \frac{2}{3} = x

∴ The graph has a vertical asymptote at x =  \frac{2}{3}

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = \frac{2}{3}

∴ The graph has a horizontal asymptote at y =  \frac{2}{3}

The graph of  y=\frac{3-2x}{2-3x} has a vertical asymptote at x =  \frac{2}{3} and a horizontal asymptote at y =  \frac{2}{3}

Second question:

The graph has a horizontal asymptote at y = -3

<em />

<em>means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3</em>

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∵ In answer A the quotient is 1 because x up and down have

  coefficient 1

∵ In answer B the quotient is -\frac{1}{3} because the coefficient of x

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∵ In answer D the quotient is -1 because the coefficient of x

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∵ In answer C the quotient is -3 because the coefficient of x up

   is -3 and down is 1

∴ The graph of equation y=\frac{1-3x}{2+x} has a horizontal asymptote at y = -3

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