If 162.35 g aluminum hydroxide are dissolved in 6750 mL of solution, the concentration of the solution is 0.308M
<h3>How to calculate concentration?</h3>
The concentration of a solution can be calculated using the following formula:
Molarity = no of moles ÷ volume (L)
However, the number of moles in 162.35g of Al(OH)3 must be calculated as follows:
Molar mass of Al(OH)3 = 78g/mol
no of moles = 162.35g ÷ 78mol
no of moles = 2.08mol
Molarity = 2.08mol ÷ 6.75L
Molarity = 0.308M
Therefore, if 162.35 g aluminum hydroxide are dissolved in 6750 mL of solution, the concentration of the solution is 0.308M.
Learn more about molarity at: brainly.com/question/2817451
Answer:
atom &bond
Explanation:
atom is strong due to the bond
Answer:
a. What makes this an oxidation-reduction reaction? (1 point)
Loss of electron by the aluminum and the gain of electron by the silver
b. Write the half-reactions showing the oxidation and reduction reactions. Identify which is the oxidation reaction and which is the reduction reaction. (3 points)
oxidation half reaction: Al → Al3+ + 3e-
Reduction half reaction: Ag+ + e- → Ag
c. What is oxidized in the reaction? What is reduced? (2 points)
Aluminum is oxidized and silver is reduced
d. In this simple electrochemical cell, what functions as the anode? What is the cathode? (3 points)
In a simple electrochemical cell the electrode where oxidation takes place is the anode. And the electrode where reduction reaction happens is the cathode.
e. Is this a galvanic cell or electrolytic cell? Explain your answer. (2 points)
An electrolytic cell because the reaction converts electrical energy into chemical energy
Not sure about e and f!
Answer:
Density is an intensive property
Explanation:
The intensive properties don´t depend on mass or size, if you have a liter of water, this litter have a density equal 1000 kg/m^3. If zo have 250 liters of water, the density is 1000 kg/m^3 too.
The density does not change with the addition or substraction of matter.
I hope I have been clear.
Answer:
Your answer choice is D
Explanation:
I just got it right on USATestprep :))