Answer:
Percent by mass of water is 56%
Explanation:
First of all calculate the mass of hydrated compound as,
Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g
Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g
Mass of Oxygen = O × 14 = 16 × 14 = 224 g
Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g
Mass of Na₂S0₄.10H₂O = 322.24 g
Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...
Mass of water = 10 × 18.02
Mass of water = 180.2 g
Now, we will apply following formula to find percent of water in hydrated compound,
%H₂O = Mass of H₂O / Mass of Hydrated Compound × 100
Putting values,
%H₂O = 180.2 g / 322.24 g × 100
%H₂O = 55.92 % ≈ 56%
First structure is CH₃-CH₃. It is an alkane with two carbon atoms hence it is called ethane.
Second structure is CH₃-CH₂-CH₂-CH₃. It is an alkane with four carbon atoms hence it is called butane.
Third structure is CH₄. It is an alkane with one carbon atom hence it is called methane.
Fourth structure is CH₃-CH₂-CH₃. It is an alkane with three carbon atoms hence it is called propane.
Answer:c c c c c c c c c c c c c c c c c c c c c c c c c c cc c c c c c c c c
cc
Explanation:
It is given that the charge on potassium is +1 i.e. Potassium is a cation, K⁺
The charge on selenium is given as -2, i.e. selenium is an anion, Se²⁻
The two ions are shown to combine to form a molecule: KXSeY where X and Y correspond to the proportions in which the two atoms combine.
Since the molecule is neutral, the positive and negative charges need to be balanced. This is possible only if 2 units of K⁺ combines with 1 unit of Se²⁻.
Therefore, the formula would be K₂Se
X = 2 and Y = 1
