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4 years ago

Which term best describes an animal that eats dead and decaying meat? A. predator B. producer C. decomposer D. scavenger

2 answers:

8 0

These types of animals are referred to as D. scavengers.

Scavenger animals are adapted to feed on dead and decaying meat and usually feed on the carcasses left over by predatory animals. An example is how vultures pick off the meat from a zebra carcass that has been left over after a lion pack has finished eating from it.

VladimirAG [237]4 years ago

8 0

I think its d
holp this helps :D

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how would the woodpecker population in a forest area most likely be affected if a housing devolpment is built in that area

alexira [117]

The entire woodpecker population would be DESTROYED

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3 years ago

Read 2 more answers

What other kinds of empirical evidence can be used to show common ancestry among organisms?

kotegsom [21]

Answer:There are, however, other forms of empirical evidence that support the theory of evolution. The fossil record, anatomical and embryological homologous, and genetic similarities are also used to support the theory of evolution. Many pieces of evidence support the theory that birds and dinosaurs are related.

Explanation:hope i am helpful

4 0

4 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant

Vanyuwa [196]

<h3>Answer:</h3>

Excess Reagent = NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

2 NBr₃ + 3 NaOH → N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

2 moles NBr₃ reacts with = 3 moles of NaOH

So,

40 moles of NBr₃ will react with = X moles of NaOH

Solving for X,

X = (40 mol × 3 mol) ÷ 2 mol

X = 60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

6 0

3 years ago

Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)

Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) (1)

We can write the above reaction in two reactions, one for oxidation and the other for reduction:

Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻ (2)

Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s) (3)

We can see that Li⁰ is oxidizing to Li⁺ (by losing one electron) in the lithium acetate (reaction 2) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by gaining two electrons) (reaction 3).

We must remember that the reducing agent is the one that will be oxidized by reducing another element and that the oxidizing agent is the one that will be reduced by oxidizing another species.

In reaction (1), the reducing agent is Li (it is oxidizing to Li⁺), and the oxidizing agent is Fe(CH₃COO)₂ (it is reducing to Fe⁰).

Therefore, the reducing agent in reaction (1) is lithium (Li).

Learn more here:

brainly.com/question/10547418?referrer=searchResults

brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0

3 years ago

The molar heat of vaporization of water is 40.7 kJ mol . How much heat must be absorbed to convert 50.0 grams of liquid water at

podryga [215]

Molar mass of water 18g/mol

Number of mols = 50.0g/18g/mol =2.78 mol

Heat absorbed = 40.7 kj/mol * 2.78 mol = 113.1 kj.

8 0

3 years ago