On the cooling curve below, between points Dand Ethe substance is changing from

13 moles of water to molecules

FromTheMoon [43]

I’m confused what are you asking exactly?

6 0

3 years ago

alina1380 [7]

Answer:

Differences

• Space is everything in the universe beyond the top of Earth's atmosphere - The moon, Stars, Milky way, etc.

• In space, no one can hear you scream. This is because there is no air in space, i.e, it's vacuum.

• Earth is a planet on solar system. It is the only planet where life exists!!

• Earth is also called "blue sky" cause it has 75% water.

Similarities

•They need oxygen for survival: Man, animals in earth and space need oxygen for survival.

•Water is also need to stay alive.

•Food is very paramount to both man, animal s and organisms.

•Shelter, we all ned a place to lay our head in other to be safe.

•Air everywhere in the atmosphere.

•Water, air, food and shelter are available on earth but their availability differs in space.

•Astronaut need to bring everything one need in space with him or her from Earth. They often recycle the things they bring.

Hope it helps :)

4 0

2 years ago

Read 2 more answers

Balancing the reaction by oxidation number method k2cr2o7+sncl2+hcl

Mumz [18]

Answer:

$K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)$

Explanation:

The products of this reaction are given by:

$K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)$

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

$Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)$

The following steps should be taken:

balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:

$Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)$

balance oxygen atoms by adding 7 water molecules on the right:

$Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

balance the hydrogen atoms by adding 14 protons on the left:

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

Similarly, tin(II) cation becomes tin(IV) cation:

$Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-$

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)$

$3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-$

Add them together:

$Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)$

Adding the ions spectators:

$K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)$

7 0

3 years ago

7) What is the hydrogen concentration of a solution with a pH of 2.1? *

lesya [120]

Answer:

Hydrogen concentration = 7.94×10^-3 M

Explanation:

from potenz Hydrogen ( pH ) definition

pH = -log[H+]

2.1 = -log[H+]

2.1/-log = -log[H+]/-log

10^-2.1 = [H+]

[H+] = 7.94×10^-3M

8 0

3 years ago

Write the ions present in a solution of na3po4. express your answers as chemical formulas separated by a comma. offset subscript

dexar [7]

Sodium/natrium is a metal from first column group so it should have one 1+ charge. Phosphate ion has 3- charge. That is why there 3 natrium ion for 1 phosphate ion when this molecule is dissolved in water. The ion formula would be:

(Na) $_{3}$ (PO $_{4}$ ) ==> 3 Na $^{+}$ + PO $_{4} ^{3-}$

5 0

3 years ago