Given the Latin meaning of the cogito, we can confirm that it is roughly translated and summarized by the phrase <em><u>"I think, therefore I am"</u></em>.
Cogito, ergo sum or "The Cogito" is an extremely popular, well-known philosophical phrase credited to <em><u>Rene Descartes</u></em>. This Latin phrase is roughly translated as <em><u>"I think, therefore I am"</u></em>, which appeared originally in "The Principles of Philosophy", and was later translated to a variety of languages in an attempt to reach a wider public, most notably into Latin.
To learn more visit:
brainly.com/question/16853649?referrer=searchResults
Hello!
If there's an air bubble inside the buret, and the bubble escapes the buret during the titration the initial volume lecture (Vi) would be lower (closer to 0) than the actual one, and the recorded consumed volume (ΔV=Vf-Vi) would be higher than the actual one and thus the calculated concentration of the hydrochloric acid would be higher than the real one.
Have a nice day!
Depends on how the sword is made, what materials are used and temperature used but yes they can shatter.
When molecules cool down they stop vibrating and moving as much and so they "shrink" and the metal of the sword becomes brittle. sometimes they shrink at different phases which cause tension in the sword if this tension is strong enough it can cause the metallic bonds to break causing the sword to shatter.
hope that helps
Answer: The concentration of 
is 0.234 M
Explanation:
According to the neutralization law,
where,
= basicity = 2
= molarity of solution = ?
= volume of solution = 50.0 ml
= acidity of 
= 1
= molarity of solution = 0.375 M
= volume of solution = 62.5 ml
Putting in the values we get:
Therefore concentration of is 0.234 M
Answer:
∆H° rxn = - 93 kJ
Explanation:
Recall that a change in standard in enthalpy, ∆H°, can be calculated from the inventory of the energies, H, of the bonds broken minus bonds formed (H according to Hess Law.
We need to find in an appropiate reference table the bond energies for all the species in the reactions and then compute the result.
N₂ (g) + 3H₂ (g) ⇒ 2NH₃ (g)
1 N≡N = 1(945 kJ/mol) 3 H-H = 3 (432 kJ/mol) 6 N-H = 6 ( 389 kJ/mol)
∆H° rxn = ∑ H bonds broken - ∑ H bonds formed
∆H° rxn = [ 1(945 kJ) + 3 (432 kJ) ] - [ 6 (389 k J]
∆H° rxn = 2,241 kJ -2334 kJ = -93 kJ
be careful when reading values from the reference table since you will find listed N-N bond energy (single bond), but we have instead a triple bond, N≡N, we have to use this one .
