Answer:
2.86 kJ
Explanation:
When a substance is heated and there's no phase change happening, the amount of heat (Q) necessary for the heating can be calculated by:
Q = m*c*ΔT
Where m is the mass, c is the specific heat capacity of the substance, and ΔT is the variation of temperature. So, in this case, m = 53.8 g, c = 1.05 J/g°C, and ΔT = 50.6 K. The temperature variation is the same in °C and K, so:
Q = 53.8*1.05*50.6
Q = 2858.394 J (÷1000)
Q = 2.86 kJ
Answer:
yes....
Explanation:
Let me explain the molecular orbital diagram of N2 using its diagram.
one atom of nitrogen has 7 electrons so a N2 molecule will have 14 electrons
so first 2 electrons go in 1s sigma bond
next 2 in 1s sigma anti bond orbital
next 2 in 2s sigma bond orbital
next 2 in 2s sigma anti bond orbital
next 2 in 2pz sigma bond( assuming that z axis is the internuclear axis ) orbital
Answer:
At the higher altitude, the new volume is 750.2L
Explanation:
If we decompose the Ideal Gases Law for the two situations (initial and final), we can determine this relaion:
P₁ . V₁ / T₁ = P₂ . V₂ / T₂
Number of moles does not change, and R stays the same.
Let's make some conversions, before:
752 mmHg . 1 atm / 760mmHg = 0.989 atm
24.3°C + 273 = 297.3K
0.0708 bar . 0.986 atm / 1bar = 0.070 atm
-5.41°C + 273 = 267.59 K
We replace: (0.989 atm . 59L) / 297.3K = (0.070 atm . V₂) / 267.59K
[(0.989 atm . 59L) / 297.3K] . 267.59K = 0.070 atm . V₂
52.5 atm.L = 0.070 atm . V₂
V₂ = 52.5 atm.L / 0.070atm = 750.2L
I think the correct answer from the choices listed above is the first option. Compared to compounds that possess only dipole-dipole intermolecular forces, compounds that possess hydrogen bonding generally have <span>higher melting points. This is because hydrogen bonding is a stronger force than dipole-dipole.</span>