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3 years ago

Which electrode do copper ions move towards?

1 answer:

6 0

Copper sulfate, CuSO4 ===> (Cu^2+) (SO4^2-). 
That means copper ions have a positive charge in the solution of this compound and are therefore attracted to the negative electrode, cathode. Just wanted to clear that out because "it accepts electrons there" is an invalid and ambiguous answer. 
Good luck.

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Select all of the answers that apply. Which of the following are ways the atmosphere supports life?

kupik [55]

Answer:

the atmosphere supports life by giving us simple things like wood.

5 0

4 years ago

15. How many moles of CaCl are in 250. mL of 3.00 M of CaCl solution?

Jobisdone [24]

Answer:D.0.75
Answer d

8 0

3 years ago

What is the mass of an osmium block that measures 6.70 cm × 9.20 cm × 3.30 cm? The density of osmium is given as 22.610 g/cm3. N

alexira [117]

Answer:

m= 4,599.145 g

Explanation:

Let m = mass, d = density and V = volume of the osmium block.

m = d x V

m = 22.610 g/cm3 x (6.70 x 9.20 x 3.3) cm3

m = 4,599.145 g

7 0

3 years ago

Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.

Cerrena [4.2K]

Answer:

Answer :

The total pressure inside the cylinder is, 6.7 atm

The mole fraction of N_2 in the mixture is, 0.52

Solution :

First we have to calculate the total pressure inside the cylinder.

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

P_T=p_{N_2}+p_{O_2}+p_{Ar}+p_{He}

Now put all the given values is expression, we get the total pressure inside the cylinder.

P_T=3.5+2.8+0.25+0.15=6.7atm

Now we have to calculate the mole fraction of N_2 in the mixture.

Formula used :

pN_2=XN_2 x P_T

where,

P_T = total pressure = 6.7 atm

pN_2 = partial pressure of nitrogen gas = 3.5 atm

XN_2 = mole fraction of nitrogen gas = ?

Now put all the given values in the above formula, we get

3.5atm=XN_2 x 6.7atm

XN_2=0.52

Therefore, the total pressure inside the cylinder is, 6.7 atm and the mole fraction of N_2 in the mixture is, 0.52

Hope it helps answer the question:)

5 0

3 years ago

Calculate the energy required to produce 7.00 mol Cl2O7 on the basis of the following balanced equation. 2Cl2(g) + 7O2(g) + 130

KatRina [158]

Explanation:

As the given chemical reaction equation is as follows.

$2Cl_{2}(g) + 7O_{2}(g) + 130 kcal \rightarrow 2Cl_{2}O_{7}(g)$

Also, it is given that for 2 moles the energy required is 130 kcal. This means that energy required for 1 mole is calculated as follows.

1 mole = $\frac{130 kcal}{2}$

= 65 kcal

Hence, energy required for 7 moles will be calculated as follows.

Energy required = $7 \times 65 kcal$

= 455 kcal

Thus, we can conclude that energy required to produce 7.00 mol $Cl_{2}O_{7}$ on the basis of given reaction is 455 kcal.

3 0

4 years ago