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3 years ago

How do atoms form new substances?

1 answer:

5 0

Atoms combine as the electrons from each atom are attracted to the nuclei of the atoms. This results in bonds ranging from 100% covalent to bonds with high ionic character. The combination of atoms to form compounds occurs when the compounds being formed are at lower energy than the original atoms

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PLEASE HURRY AND TELL ME THE ANWERS

lesantik [10]

Answer:

Explanation:

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2 years ago

Which of the following organisms carry out photosynthesis?

andre [41]

Plants, algae, and a group of bacteria called cyanobacteria are the only organisms capable of performing photosynthesis. They use light to manufacture their own food, they are called photoautotrophs (literally, “self-feeders using light”).

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2 years ago

3. What causes the plates to be pulled apart? PLEASE HELP

Tamiku [17]

Answer:

Hot magma rises from the mantle at mid-ocean ridges pushing the plates apart. Earthquakes occur along the fractures that appear as the plates move apart.:

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3 years ago

Read 2 more answers

Ammonia is produced by the following reaction. 3H2(g) + N2(g)

777dan777 [17]

Answer:

The hydrogen produces the smaller amount of ammonia.

Step-by-step explanation:

We are given the masses of two reactants, so this is a limiting reactant problem.

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 28.02 2.016 17.03

N₂ + 3H₂ ⟶ 2NH₃

Mass/g: 70.0 7.00

1. Calculate the moles of N₂ and H₂

Moles N₂ = 70.0 × 1/28.02

Moles N₂ = 2.498 mol N₂

Moles H₂ = 7.00 × 2.016

Moles H₂ = 3.472 mol N₂

=====

2. Calculate the moles of NH₃ from each reactant

From N₂:

The molar ratio is 2 mol NH₃/1 mol N₂

Moles of NH₃ = 2.498 × 2/1

Moles of NH₃ = 4.996 mol NH₃

From H₂:

The molar ratio is 2 mol NH₃/3 mol H₂

Moles of NH₃ = 3.472 × 2/3

Moles of NH₃ = 4.139 mol NH₃

======

3. Identify the limiting reactant

The limiting reactant is H₂, because it produces fewer moles of NH₃.

4 0

3 years ago

Calculate the specific heat in J/(g·ºC) of an unknown substance if a 2.50-g sample releases 12.0 cal as its temperature changes

Degger [83]

Answer:

$\fbox{c = - 4.01 \: joule/g°C}$

Step by step explanation:

Given:

Mass of given sample (m) = 2.50 g

Initial temperature (T1) = 25°C

Final temperature (T2) = 20°C

Heat Energy Q = 12 cal

To find:

 $Specific \: Heat \: c = \: ?$ 

Solution:

We know that,

Specific heat of any substance is directly proportional to the mass and change in temperature.

Represented by equation,

$Q = mc \triangle T$

Where,

Q = Heat Energy

m = mass of given sample

c = specific heat

∆T = change in temperature

Substituting corresponding values,

$Q = mc \triangle T \\ 12 = 2.5\times c \times (20-25) \\ c = \frac{12}{2.5 \times ( - 5)} \\ c = - 0.96 \: cal/g°C \\$

We also know that,

$1 \: cal = 4.184 \: joules$

multiplying above answer by 4.184,

$c = - 0.96 \times 4.184 \\ \fbox{c = - 4.01 \: joule/g°C}$

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6 0

2 years ago