15. How many moles of CaCl are in 250. mL of 3.00 M of CaCl solution?

Study the Lewis dot diagram for nitrogen. Explain what is correct and what is incorrect about the diagram. Use details to suppor

Verdich [7]

Answer:

The Lewis dot diagram is supposed to have dots on each side. What's incorrect is that there isn't a dot on the bottom, only the left and right side and the top. What's correct about this is that there are 5 outer valence electrons, and they correctly put 5 dots, even though they're in the wrong place.

Explanation:

4 0

3 years ago

When 25.0 mL of a solution of 1.4 x 10-3 M silver nitrate is mixed with 60.0 mL of a solution of 7.5 x 10-4 M sodium chloride a)

LUCKY_DIMON [66]

Step one write the equation for dissociation of AgNO3 and NaCl

that is AgNO3-------> Ag+ + NO3-

NaCl--------> Na+ + Cl-
then find the number of moles of each compound
that is for AgNO3 = ( 1.4 x10^-3 ) x 25/1000= 3.5 x10^-5 moles
Nacl= (7.5 x10^-4)x 60/1000= 4.5 x10^-5 moles

from mole ratio the moles of Ag+= 3.5 x10^-5 moles and that of Cl-= 4.5 x10^-4 moles

then find the total volume of the mixture
that is 25ml + 60 Ml =85ml = 0.085 liters

The Ksp of Agcl = (Ag+) (cl-), let the concentration of Ag+ be represented by x and also the concentration be represented by x

ksp (1.8 x10^-10) is therefore= x^2

find the square root x=1.342 x10^-5

Ag+ in final mixture is = moles of Ag+/total volume - x
that is {(3.5 x10^-5)/0.085} - 1.342 x10^-5=3.98x10^-4

Cl- in the final mixture is =(4.5 x10^-5 /0.085) - 1.342 x10^-5= 5.16 x10^-4

4 0

3 years ago

Read 2 more answers

What is the relationship between developed land, population and resource use?

givi [52]

Explanation:

While both developed and developing countries have contributed to global environmental problems, developed countries with 85% percent of the gross world product and 23% of its population account for the largest part of mineral and fossil-fuel consumption, resulting in significant environmental impacts

3 0

2 years ago

The [OH-] of an aqueous solution is 3.5 x 10-5. What is the [H+]?

Sergeeva-Olga [200]

Answer: The concentration of hydrogen ion in the given solution is $2.81 \times 10^{-10}$ .

Explanation:

pOH of a solution is the negative logarithm of concentration of hydroxide ions.

Hence, if $[OH^{-}]$ is $3.5 \times 10^{-5}$ then its pOH value is calculated as follows.

$pOH = -log [OH^{-}]\\= -log (3.5 \times 10^{-5})\\= 4.45$

Now, the relation between pH and pOH is as follows.

pH + pOH = 14

pH + 4.45 = 14

pH = 14 - 4.45

= 9.55

And, pH is the negative logarithm of concentration of hydrogen ions. Hence, $[H^{+}]$ is calculated as follows.

$pH = -log [H^{+}]\\9.55 = -log [H^{+}]\\H^{+} = 2.81 \times 10^{-10}$

Thus, we can conclude that the concentration of hydrogen ion in the given solution is $2.81 \times 10^{-10}$ .

4 0

3 years ago

The relative abundances of the stable isotopes of the elements are not entirely constant. For example, in some geologic samples

Mrac [35]

<u>Answer:</u> The other isotope is $_{37}^{87}\textrm{Rb}$

<u>Explanation:</u>

Beta decay is defined as the decay process in which a neutron gets converted to a proton and an electron.

In this decay process, beta particle is emitted. The emitted particle carries a charge of -1 units and has a mass of 0 units. The released beta particle is also known as electron.

The general equation for the beta decay process follows:

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta$

The chemical equation for the beta decay of an isotope that produces Sr-87 isotope follows:

$_{37}^{87}\textrm{Rb}\rightarrow _{38}^{87}\textrm{Sr}+_{-1}^0\beta$

The isotope that undergoes beta decay to form Strontium-87 isotope is Rubidium-87

Hence, the other isotope is $_{37}^{87}\textrm{Rb}$

4 0

3 years ago