Answer:
<h2><u>Reason:</u></h2>
Catalyst is used as a very fine powder and larger pieces of iron are not used. This is because the surface area of catalyst needs to be large so that more of the surface is exposed to the substrate and more of the substrate is catalyzed.
<h2><u>Important Info:</u></h2>
=> Larger Pieces of Iron has a smaller surface area than the fine particles.
=> Larger the surface area of catalysts/enzymes , more will be the reaction rate and vice versa.
Hope this helped!
<h2>~AnonymousHelper1807</h2>
Answer:Zn(s) + H2SO4(aq) → ZnSO4(aq) + H2(g)
O2Zn(s) + H2SO4(aq) → 22nH(aq) + SO4(s)
Explanation:
Answer:
4, 16,
Explanation:
SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).
Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.
1.one substance must dissolve another : the solvent breaks the the solute causing it to dissociate into the solvent it can be both solids or gases that dissolve in the solute
2.the melting point will be higher than 100 degrees as the salt causes the solution to gain a higher melting point
3.either released or absorbed : energy is required to dissolve the solute but the solute may also release energy
4.the salt dissolved most quickly in the warm water : as there is more energy for the solute to dissolve
hope that helps
Answer:
fe3o4+4h2 - 3fe + 4h2o
therefore coefficient is 4
