Answer:
![\alpha =10.93radian/sec^2](https://tex.z-dn.net/?f=%5Calpha%20%3D10.93radian%2Fsec%5E2)
Explanation:
We have given given the final angular velocity ![\omega _{final}=13.5rad/sec](https://tex.z-dn.net/?f=%5Comega%20_%7Bfinal%7D%3D13.5rad%2Fsec)
And ![\omega _{initial}=22rad/sec](https://tex.z-dn.net/?f=%5Comega%20_%7Binitial%7D%3D22rad%2Fsec)
Displacement ![\Theta =13.8radian](https://tex.z-dn.net/?f=%5CTheta%20%3D13.8radian)
We have to find the angular acceleration ![\alpha](https://tex.z-dn.net/?f=%5Calpha)
According to law of motion ![\omega _{final}^2=\omega _{initial}^2+2\alpha \Theta](https://tex.z-dn.net/?f=%5Comega%20_%7Bfinal%7D%5E2%3D%5Comega%20_%7Binitial%7D%5E2%2B2%5Calpha%20%5CTheta)
So ![13.5^2=22^2+2\times \alpha \times 13.8](https://tex.z-dn.net/?f=13.5%5E2%3D22%5E2%2B2%5Ctimes%20%5Calpha%20%5Ctimes%2013.8)
![\alpha =-10.93radian/sec^2](https://tex.z-dn.net/?f=%5Calpha%20%3D-10.93radian%2Fsec%5E2)
In question we have tell about magnitude only so ![\alpha =10.93radian/sec^2](https://tex.z-dn.net/?f=%5Calpha%20%3D10.93radian%2Fsec%5E2)
Answer:
tan (x eˣ) + C
Explanation:
∫ (eˣ + x eˣ) / (cos² (x eˣ)) dx
First, use u-substitution.
u = x eˣ
du = (eˣ + x eˣ) dx
∫ 1 / (cos² u) du
∫ sec² u du
tan u + C
Substitute back:
tan (x eˣ) + C
<span>C. The net force is perpendicular to the motion.
When you swing a yo-yo in a circle around your head, the net force
is the tension in the string, pointing toward the center of the circle.
There's nothing there that provides any force parallel or opposite to
the motion.
When the Earth revolves around the Sun in a circular orbit, the net force
is the gravitational force between the Sun and the Earth. There's nothing
</span>there that provides any force parallel or opposite to the motion.
<span>If it stopped spinning completely, you would get 1/2 year daylight and 1/2 year nightime!! During daytime for 6 months, the surface temperature would depend on your latitude, being far hotter that it is now at the equator than at the poles where the light rays are more slanted and heating efficiency is lower. This long-term temperature gradient would alter the atmospheric wind circulation pattern so that the air would move from the equator to the poles rather than in wind systems parallel to the equator like they are now!</span>