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muminat
3 years ago
7

The mole is 6.02 x 10 23 particles. If a person masses out the correct molar mass in grams for a substance then she would have a

n entire mole of it. If the molar mass for H2O is 18 g and Mrs. Q had 36 grams of H2O then how many molecules did she have?
Physics
1 answer:
Leto [7]3 years ago
7 0

Answer:

1 mole of H2O is 18 grams (2 g H + 16 g Oxygen)

36 / 18 = 2

So 2 moles = 2 * 6.02E23 = 12.04E23 = 1.204E24

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Hail comes straight down at a mass rate of m/Δt = 0.050 kg/s and an initial velocity of v0 = -15 m/s and strikes the roof perpen
cupoosta [38]

Answer:

F = 1.5 N

Explanation:

Let the hails are coming down with speed "v" and then rebound with the same speed in opposite direction

So here the change in the momentum of the hails is given as

\Delta P = mv - (-mv)

\Delta P = 2mv

now we know by Newton's 2nd Law

F = \frac{\Delta P}{\Delta t}

here we have

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now plug in all data

F = 0.050(2\times 15)

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3 years ago
How does water flowing over a waterfall involve both kinetic energy and potential energy?
Vinvika [58]

Answer:

While the water falls v increases and h decreases, so the kinetic energy increases and the gravitational potential energy decreases, and this happens in a way that the total energy is always the same. (If there is no friction)

Explanation:

7 0
3 years ago
Read 2 more answers
Can somebody please help me? PLEASE
ale4655 [162]

Answer:

The 1st Answer

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6 0
2 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen
bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s} (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s

b) Substitute eq. 1 in eq. 2:

f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz

7 0
3 years ago
The switch on the electromagnet, initially open, is closed. What is the direction of the induced current in the wire loop (as se
Marianna [84]

Answer:

The induced current is clockwise

6 0
3 years ago
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