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olya-2409 [2.1K]
3 years ago
10

What is the purpose of a rear view mirror in a car?

Physics
1 answer:
Nat2105 [25]3 years ago
3 0
The purpose of a rear view mirror in a car is to see behind the car, if there is any car coning or not.
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SCIENCE whoever gets this first will get a brainlest
gulaghasi [49]

Answer:

im not 100% sure i should be doing this but i found a website that will help a ton.

https://geo.libretexts.org/Courses/Gettysburg_College/Book%3A_An_Introduction_to_Geology_(Johnson_Affolter_Inkenbrandt_and_Mosher)/02%3A_Plate_Tectonics/2.01%3A_Alfred_Wegener%E2%80%99s_Continental_Drift_Hypothesis

6 0
3 years ago
Read 2 more answers
I really need help with the graphs
nata0808 [166]

Answer:

t = 2s

Explanation:

When you're looking for instantaneous portions of a graph, of any sort really, it means you're observing a rate at a single point in time [or possibly some other variable]. It's sorta like a snapshot of a rate as opposed to an average rate over an interval. After choosing this rate we'll typically draw a straight, tangent line through it to indicate it's slope. (Tangent lines are just lines that only touch a single point on a graph or shape.)

Another thing to take note of are the values of the graph's major axes. The "y-axis" corresponds to velocity in meters per second, while the "x-axis" corresponds to time in seconds. Normally when relating the two we put "y" over the "x" and say that at any point there are "y[units]" per "x[units]". Though with instantaneous rates, we say the value of "x" is "1"; for reasons I can try to further explain later if you'd like.

With the above information in mind we can turn our attention to your graph. You're told to find the point on this graph where the instantaneous rate of acceleration is -2 m/s². The only place where the graph reflects an instantaneous rate of -2m/s² is at t = 2s. At t = 2, the rate comes out to (2[m/s]/1s), which simplifies to 2m/s². If you then draw the tangent line through the point, you'll find that the line is decreasing (going down from left to right) which means that the instantaneous rate is negative.

So at t = 2s, we have an instantaneous acceleration of -2m/s².

3 0
3 years ago
The theory of _____ suggests that the crust of the earth is divided into pieces and moves about on the upper mantle.
nirvana33 [79]
Plate tectonics and the earth is separated into many pieces which move around and create earthquakes and volcanoes
6 0
4 years ago
Read 2 more answers
Starting from rest, a runner reaches a speed of 2.8 m/s in 2.1 s. In the same time 2.1 s time, a motorcycles increases speed fro
maw [93]

Answer:

a) Acceleration of runner is 1.33 m/s²

b)  Acceleration of motorcycle is 2.85 m/s²

c) The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.

Explanation:

t = Time taken

u = Initial velocity = 0

v = Final velocity

s = Displacement

a = Acceleration

Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{2.8-0}{2.1}\\\Rightarrow a=1.33\ m/s^2

Acceleration of runner is 1.33 m/s²

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{43-37}{2.1}\\\Rightarrow a=2.85\ m/s^2

Acceleration of motorcycle is 2.85 m/s²

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{2.8^2-0^2}{2\times 1.33}\\\Rightarrow s=2.94\ m

The runner moves 2.94 m

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{43^2-37^2}{2\times 2.85}\\\Rightarrow s=84.21\ m

The motorcycle moves 84.21 m

The motorcycle moves 84.21-2.94 = 81.06 m farther than the runner.

3 0
3 years ago
How would a graph of velocity vs. Time would look like, if there was no motion at all? (Draw your graph)
Y_Kistochka [10]

Answer:

no motion means no velocity, so the y values willl always be 0 as ur time (x) value increses

Explanation:

7 0
3 years ago
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