Weight = mg Mass, m = 8kg, g ≈ 9.8 m/s² on Earth
W = 8*9.8
W ≈ 78.4 N
The statement: “According to Faraday's law, voltage can be changed by moving magnets away from the coil of wire.”, is true. Any type of movements done (away, into or out, toward, rotation, etc.) on the magnetic environment would always generate a voltage. In Faraday’s law, it is clear that there are different ways on how to generate a voltage.
Answer:
The error in tapping is ±0.02828 ft.
Explanation:
Given that,
Distance = 200 ft
Standard deviation = ±0.04 ft
Length = 100 ft
We need to calculate the number of observation
Using formula of number of observation
![n=\dfrac{\text{total distance}}{\text{deviation per tape length}}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B%5Ctext%7Btotal%20distance%7D%7D%7B%5Ctext%7Bdeviation%20per%20tape%20length%7D%7D)
Put the value into the formula
![n=\dfrac{200}{100}](https://tex.z-dn.net/?f=n%3D%5Cdfrac%7B200%7D%7B100%7D)
![n=2](https://tex.z-dn.net/?f=n%3D2)
We need to calculate the error in tapping
Using formula of error
![E_{series}=\pm E\sqrt{n}](https://tex.z-dn.net/?f=E_%7Bseries%7D%3D%5Cpm%20E%5Csqrt%7Bn%7D)
![E=\dfrac{E_{series}}{\sqrt{n}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BE_%7Bseries%7D%7D%7B%5Csqrt%7Bn%7D%7D)
Put the value into the formula
![E=\dfrac{0.04}{\sqrt{2}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B0.04%7D%7B%5Csqrt%7B2%7D%7D)
![E=\pm 0.02828\ ft](https://tex.z-dn.net/?f=E%3D%5Cpm%200.02828%5C%20ft)
Hence, The error in tapping is ±0.02828 ft.
D. The density of the sir increases and the air rises.
When coming in contact with the kettle, it becomes hot, it expands and rises up, due to lesser density as compared to the surrounding air.
B) 37 V
The potential difference between point a and point b is equal to 37 V
<h3>
Explanation:</h3>
The potential difference across a and b can be calculated by finding the equivalent resistance of the resistors R1, R2 and R3 and then by applying Ohm's law.
Given:
R1 = 3.0 Ω
R2 = 8.0 Ω
R3 = 10.0
Current = I = 5 A
<u>To calculate equivalent resistance of the circuit: </u>
R2 and R3 are connected in parallel configuration. The equivalent resistance of R2 and R3 can be calculated as
![\frac{1}{R_p} =\frac{1}{R_2} + \frac{1}{R_3} \\\\\frac{1}{R_p}=\frac{1}{8} + \frac{1}{10}= \frac{5+4}{40} = \frac{9}{40} \\\\ \frac{1}{R_p}=\frac{9}{40} \\\\R_p=\frac{40}{9}\ ohms](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BR_p%7D%20%3D%5Cfrac%7B1%7D%7BR_2%7D%20%2B%20%5Cfrac%7B1%7D%7BR_3%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7BR_p%7D%3D%5Cfrac%7B1%7D%7B8%7D%20%2B%20%5Cfrac%7B1%7D%7B10%7D%3D%20%5Cfrac%7B5%2B4%7D%7B40%7D%20%3D%20%5Cfrac%7B9%7D%7B40%7D%20%5C%5C%5C%5C%20%5Cfrac%7B1%7D%7BR_p%7D%3D%5Cfrac%7B9%7D%7B40%7D%20%5C%5C%5C%5CR_p%3D%5Cfrac%7B40%7D%7B9%7D%5C%20ohms)
Resistance R1 is in series with Rp. The equivalent series resistance is calculated as
![R_s = R1+R_p = 3+\frac{40}{9}= \frac{27+40}{9} = \frac{67}{9} = 7.44\ ohms](https://tex.z-dn.net/?f=R_s%20%3D%20R1%2BR_p%20%3D%203%2B%5Cfrac%7B40%7D%7B9%7D%3D%20%5Cfrac%7B27%2B40%7D%7B9%7D%20%3D%20%5Cfrac%7B67%7D%7B9%7D%20%3D%207.44%5C%20ohms)
Thus the given 3 resistor circuit can be written as an equivalent resistance Rs equal to 7.44 Ω through which current I passes.
By Ohm's law;
If V is the potential difference between a and b
Potential difference across points a and b = Current flowing through the circuit × Resistance between points a and b
![V = I\times R_s = 5\times 7.44 = 37.2\ V](https://tex.z-dn.net/?f=V%20%3D%20I%5Ctimes%20R_s%20%3D%205%5Ctimes%207.44%20%3D%2037.2%5C%20V)
37.2 V ≈ 37 V
Therefore, the potential difference between point a and point b is equal to 37 V