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olya-2409 [2.1K]
3 years ago
10

What is the purpose of a rear view mirror in a car?

Physics
1 answer:
Nat2105 [25]3 years ago
3 0
The purpose of a rear view mirror in a car is to see behind the car, if there is any car coning or not.
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I don’t get this question and i need help!!!
galina1969 [7]

i would say number 2

3 0
3 years ago
Rather than ascribing the increased kinetic energy of the stone to the work of gravity, we now (when using potential energy rath
Sophie [7]

Answer:

Change/ Potential

Explanation:

Work is the amount of energy required to perform an action that is for a force to cause a displacement.

From work-energy theorem, work done by body is equal to change in its kinetic energy.

Work of gravity is basically the potential energy stored in the body due to gravity. From the law of conservation of mechanical energy, increased kinetic energy comes from the change of the potential energy of the stone.

8 0
3 years ago
If you place one staple on an electronic balance, the balance still reads 0.0 grams. However, if you place
Tasya [4]
Mass of 1 staple = 6.8 g/210 staples
mass of 1 staple  = 0.032380952 g
Hope that helps!!
4 0
3 years ago
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What does it mean tha velocity is vector quantity
Wewaii [24]
It means that velocity not only has a size, but it also has a direction.

Some other vector quantities are force and acceleration.
They have sizes and directions.
 
Temperature, cost, and weight are quantities with only size and no direction.
Those are called "scalar" quantities.
7 0
3 years ago
In the diagram, q1 = +6.60*10^-9 C and q2 = +3.10*10^-9 C. Find the magnitude of the total electric field at point P. pls help?
kirza4 [7]

Answer:

|E(t)| = 1258,46 [N/C]

α = 67,5⁰  (angle with respect x-axis)

Explanation:

E(t)  Electric Field is a vector, so we need to determine module and direction

E(t)  =  E(q₁)  + E (q₂)  Where E(q₁) and E (q₂) are electric fields due to electric charge q₁ and q₂  respectively.

E(q₁) = K * q₁/ (d₁)²         K = 9 *10⁹   [N*m²/C²]    d₁ = 0,350 m

E(q₁) = 9 *10⁹ * 6,6*10⁻⁹ / 0,1225      [N*m²/C²] *C/m²

E(q₁) = 484,9 [N/C]

E(q₂) =  9 *10⁹ * 3,1*10⁻⁹ / 0,024025

E(q₂) = 1161,29

Then

|E(t)| = √ |Eq₁|² + |Eq₂|²

|E(t)| = √ ( 484,9)² +( 1161,29)²

|E(t)| = √ 235128 + 1348594,46

|E(t)| = 1258,46 [N/C]

And tanα = 1161,29/484,9        tanα =  2,395      α = 67,5⁰

The angle of the vector electric field with the x-axis

3 0
3 years ago
Read 2 more answers
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