Answer:
C
Explanation:
For a uniformly distributed mass, the center of gravity is also the geometric center. For this shape, the center is at point C.
Answer:
Setting short-term and long-term goals is very important to stay on track and motivated to improve fitness levels. You can keep track of your progress by weighing yourself every day to track weight loss, and by steadily increasing the difficulty of the exercises to track your strength improvement. It is very important to reflect on progress, so you can evaluate what you need to do in the future to remain on track, as well as seeing how much you've improved.
Answer:
10.89 J.
Explanation:
The following data were obtained from the question:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Work done =?
To obtain the workdone, we shall determine the kinetic energy of the object since work and energy has the same unit of measurement. This is illustrated below:
Mass (m) = 12.5 kg
Velocity (v) = 1.32 m/s
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 12.5 × 1.32²
K.E = 6.25 × 1.7424
K.E = 10.89 J
The kinetic energy of the object is 10.89 J. Hence, the workdone in bringing the object to rest is 10.89 J.
C
Atomic radius is the distance between the center of the nucleus to the outermost orbital shell of the atom. Assume the atom is like a football stadium and the nucleus of the atom is a ball placed at the center of the pitch. The atomic radius is from the center of the ball to the edge of the football stadium.
Explanation:
This atomic radius decreases from left to right of a periodic table because of increases in protons in the nucleus along the periodic table. This increased proton count has a higher attractive force on the electron orbitals of the atom. This decreases the atomic radius
The atomic radius of atoms down a column of the periodic table increase because an extra orbital shell is added to the atoms with every period down the column.
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The restoring force on the spring is found to have exactly the same magnitude as the stretching force. Option D
<h3>What is the restoring force?</h3>
The restoring force is the force that seeks to restore the spring to its equilibrium position. It has the same magnitude as the stretching force but acts in opposite direction.
Thus, the restoring force on the spring is found to have exactly the same magnitude as the stretching force.
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