As potential and kinetic energy increase what happens to mechanical energy?

Sphere x, of mass 2 kg, is moving to the right at 10m/s. sphere y, of mass 4 kg, is moving to the left at 10m/s. the two spheres

Neporo4naja [7]

20m/s, honestly I have know idea what the asnwer is but if i had to guess, this would be my answer.

6 0

4 years ago

A sports car moving at constant speed travels 164 m in 13.77 s. If it then brakes and comes to a stop in 3.6 s. What is its acce

Sergio039 [100]

Answer:

a = - 0.3376 g's

Explanation:

The sports car has a constant speed when travelling. Covered 164 m in 13.77 s. Thus, speed = 164/13.77 m/s

It brakes and now comes to a stop in 3.6 s.

Thus final velocity = 0 m/s

Formula for acceleration is;

a = (v - u)/t

a = (0 - (164/13.77))/3.6

a = -3.308 m/s²

In terms of g's", where 1.00 g = 9.80 m/s², we have;

a = -3.308/9.8 g's

a = - 0.3376 g's

4 0

3 years ago

The difference between generalized and specialized transduction is:

nikitadnepr [17]

When foreign DNA is introduced in a cell, that is called transduction.

<span>Specialized transduction is when restricted set of genes speciifc,DNA fragments are introduced. On the other hand in generalized or random transduction transfer the genes is accidently.</span>

8 0

4 years ago

What is 4 differences between saturated unsaturated and supersaturated solutions

Dennis_Churaev [7]

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible.

3 0

3 years ago

An electric motor spins at 1000 rpm and is slowing down at a rate of 10 t rad/s2 ; where t is measured in seconds. (a) If the mo

REY [17]

Answer:

a) The tangential component of acceleration at the edge of the motor at $t = 1.5\,s$ is -1.075 meters per square second.

b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Explanation:

The angular aceleration of the electric motor ( $\alpha$ ), measured in radians per square second, as a function of time ( $t$ ), measured in seconds, is determined by the following formula:

$\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right]$ (1)

The function for the angular velocity of the electric motor ( $\omega$ ), measured in radians per second, is found by integration:

$\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right]$ (2)

Where $\omega_{o}$ is the initial angular velocity, measured in radians per second.

a) The tangential component of aceleration ( $a_{t}$ ), measured in meters per square second, is defined by the following formula:

$a_{t} = R\cdot \alpha$ (3)

Where $R$ is the radius of the electric motor, measured in meters.

If we know that $R = 7.165\times 10^{-2}\,m$ , $\alpha = 10\cdot t$ and $t = 1.5\,s$ , then the tangential component of the acceleration at the edge of the motor is: