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Digiron [165]
2 years ago
6

A force that opposes motion in moving parts is friction. A. true b false

Physics
2 answers:
Cerrena [4.2K]2 years ago
8 0
A force that opposes motion in moving parts is friction. A
Julli [10]2 years ago
8 0
This is true. Friction is the resistance that one surface or object encounters when moving over another. The definition described above is worded differently but both definitions still mean the same thing.

Hope this helps!! ☺️
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For a two-level system, the weight of a given energy distribution can be expressed in terms of the number of systems, N, and the
Nikitich [7]

Answer:

W = N!/(n0! * n1!)

Explanation:

Let n0 = number of particles in the lowest energy state

n1 = number of particles in the excited energy state.

Using this, we can say that N = n0 + n1

From this we can then express the weight, W of the close system by finding the factorials of each particles

W = N!/(n0! * n1!)

Hence, the weight W is expressed as W = N!/(n0! * n1!)

7 0
2 years ago
An asteroid is on a collision course with Earth. An astronaut lands on the rock to bury explosive charges that will blow the ast
forsale [732]

Answer:

The maximum radius the asteroid can have for her to be able to leave it entirely simply by jumping straight up is approximately 1782.45 meters

Explanation:

Whereby the height the astronaut can jump on Earth = 0.500 m, we have the following kinematic equation;

v² = u² - 2·g·h

Where;

v = The final velocity

u = The initial velocity

g = The acceleration due to gravity ≈ 9.8 m/s²

h = The height she jumps

At the maximum height, h_{max} = 0.500 m, she jumps, v = 0, therefore, we have;

0² = u² - 2·g·h_{max}

u² = 2 × 9.8 × 0.5 = 9.8

u = √9.8 ≈ 3.13

u = 3.13 m/s

Her initial jumping velocity ≈ 3.13 m/s

Escape velocity, v_e = \sqrt{\dfrac{2 \cdot G \cdot M}{r} }

Where;

M = The mass of the asteroid

G = The Universal gravitational constant = 6.67408 × 10⁻¹¹ m³/(kg·s²)

r = The radius of the asteroid

The average density of the Earth = 5515 kg/m³

The mass of the asteroid, M = Density × Volume = 5515 kg/m³× 4/3 × π × r³

The escape velocity, she has, v_e ≈ 3.13 m/s is therefore;

3.13 = \sqrt{\dfrac{2 \times 6.67408 \times 10^{-11} \times 5515 \times \frac{4}{3} \times \pi \times r^3}{r} } = r \times \sqrt{3.084 \times 10^{-6}}

r = \dfrac{3.13}{ \sqrt{3.084 \times 10^{-6}}} \approx 1782.45

Therefore, the maximum radius of the asteroid can have for her jumping velocity to be equal to the escape velocity for her to be able to leave it entirely simply by jumping straight up = r ≈ 1782.45 meters.

7 0
2 years ago
Please help me answer these questions ASAP !
vodomira [7]
1. Layer A is the oldest. The law of superposition says that the oldest layer is at the bottom whilst the newest is at the top.
2. The law of original horizontality.
3. The law of original lateral continuity.
3 0
3 years ago
If you apply a force of 100 N to the level, how much force is applied to lift the crate?
Kaylis [27]
I believe that the answer is B. 133 N
4 0
3 years ago
What is the pH of neutral substance?
Lunna [17]

Answer:

7

Explanation:

A substance that is neither acidic nor basic is neutral. The pH scale measures how acidic or basic a substance is. The pH scale ranges from 0 to 14. A pH of 7 is neutral.

8 0
3 years ago
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