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2 years ago

A force that opposes motion in moving parts is friction. A. true b false

Physics

2 answers:

Cerrena [4.2K]2 years ago

8 0

A force that opposes motion in moving parts is friction. A

Julli [10]2 years ago

8 0

This is true. Friction is the resistance that one surface or object encounters when moving over another. The definition described above is worded differently but both definitions still mean the same thing.

Hope this helps!! ☺️

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a trolley of mass 20kg was originally at rest on a smoth horizontal surface. bu how much will it accelerate if a pulling force o

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just divide 22 N by 20 kg to get the acceleration in m/s2

Explanation:

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2 years ago

The grant that considered the foundation of financial aid is the:

navik [9.2K]

Answer:

I think it is the Federal Pell Grant Program.

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2 years ago

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g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin

Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

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And $\theta = 90$ so

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2 years ago

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Let’s say I am in a bumper car and have a velocity of 14 m/s, driving in the positive x-direction. I and my bumped car have a ma

AlekseyPX

Answer:

160 kg

12 m/s

Explanation:

$m_1$ = Mass of first car = 120 kg

$m_2$ = Mass of second car

$u_1$ = Initial Velocity of first car = 14 m/s

$u_2$ = Initial Velocity of second car = 0 m/s

$v_1$ = Final Velocity of first car = -2 m/s

$v_2$ = Final Velocity of second car

For perfectly elastic collision

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow m_2v_2=m_{1}u_{1}+m_{2}u_{2}-m_{1}v_{1}\\\Rightarrow m_2v_2=120\times 14+m_2\times 0-(120\times -2)\\\Rightarrow m_2v_2=1920\\\Rightarrow m_2=\frac{1920}{v_2}$

Applying in the next equation

$v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 120}{120+\frac{1920}{v_2}}\times 14+\frac{m_2-m_1}{m_1+m_2}\times 0\\\Rightarrow \left(120+\frac{1920}{v_2}\right)v_2=3360\\\Rightarrow 120v_2+1920=3360\\\Rightarrow v_2=\frac{3360-1920}{120}\\\Rightarrow v_2=12\ m/s$

$m_2=\frac{1920}{v_2}\\\Rightarrow m_2=\frac{1920}{12}\\\Rightarrow m_2=160\ kg$

Mass of second car = 160 kg

Velocity of second car = 12 m/s

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3 years ago

What kind of employment is regarded as national level employment?

yanalaym [24]

Answer:

In most cases, the sources of information for both levels are same as follows:

Verbal or personal contacts : This information is transferred through verbal method. ...

Different media: Media is one of the best sources of information in these days.

Explanation:

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2 years ago