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brilliants [131]
3 years ago
6

Find the area of a triangle with a base of 28 cm and a height of 20 cm.

Mathematics
2 answers:
DedPeter [7]3 years ago
3 0

Answer:

280 cm2

Step-by-step explanation:

28x20 equals 560, divide by two because its a triangle thus equaling 280.

steposvetlana [31]3 years ago
3 0

Answer:

280

Step-by-step explanation:

The formula for the area of a triangle is A=h*b÷2 so, we multiply 28*20 = 560, then we divide 560 ÷ 2 = 280, therefore, 280 is our answer

Hope I helped :)

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nikitadnepr [17]

Answer:

40

Step-by-step explanation:

\frac{35x - 2 - 93}{2}  = 7x + 5

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17.5x - 47.5 = 7x + 5

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7(5) + 5 = 40

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2 years ago
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Aleksandr-060686 [28]
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3 years ago
A (0, 2) and B (6,6) are points on the straight line ABCD.
elena-14-01-66 [18.8K]

Answer:

(18, 14)

Step-by-step explanation:

We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.

The distance formula states that the distance between two points (x_1,y_1) and (x_2,y_2), the distance is denoted by: \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}. Let's find the distance between A and B:

d = \sqrt{(6-0)^2+(6-2)^2}=\sqrt{6^2+4^2} =\sqrt{36+16} =\sqrt{52} =2\sqrt{13}

Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:

4√13 = \sqrt{(6-a)^2+(6-b)^2}

Square both sides:

208 = (6 - a)² + (6 - b)²

Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:

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208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²

208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52

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b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14

So point D has coordinates (18, 14).

8 0
3 years ago
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Step-by-step explanation:

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