30 = 5(m) + 7(n)
5(a) + 30 = 7(a)
(a) is the number of visits!
15 = (a)
5(15) = 75 + 30 = 7(15) = $105
Step-by-step explanation:
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Answer:
495 combinations of 4 students can be selected.
Step-by-step explanation:
The order of the students in the sample is not important. So we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

How many combination of random samples of 4 students can be selected?
4 from a set of 12. So

495 combinations of 4 students can be selected.
The solutions you get when you solve the formula are the corresponding y coordinates to your x value. So say a point on your graph is (2,3). The first number is x and the second is y. (x,y). The number you plug into your function is x,or in this case: 2. The solution to the equation when the x value is plugged in is y, or 3. Therefore, giving you a point on your graph.
Let Sara weight =x+25
amber wiegh =x
x+25+x=205
x= 90
Sara weight is 90+25= 115