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3 years ago

-18xy3 (9xy – 2y4 + 10x)

Mathematics

1 answer:

satela [25.4K]3 years ago

7 0

The Answer Is -54xy(9xy-2y^4+10x)

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(20m + 3) - (7 m - 5)<br> Find the difference

DedPeter [7]

20m-7m= 13m
3--5=8
13m+8

8 0

3 years ago

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Write down the 5th term in the sequence given by t(n) = n^2 +2n

madam [21]

So it our equation would be t(5)=5^2+2(5)
25+10=35 :)

5 0

3 years ago

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Simplify: (25 + 17) – |37 – 13| A. 15 B. 18 C. 20 D. 21

vaieri [72.5K]

First we solve modulus

| 37-13| =|24|= 24

Now solving Bracket

25+17 = 42

Therefore, 42 - 24 = 18

3 0

3 years ago

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The diameter of a circle measures 22 yd. What is the circumference of the circle?

luda_lava [24]

Answer:

69.08 yd

Step-by-step explanation:

7 0

3 years ago

(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$

We rewrite, moving the exponent within the radical:

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =$

We can rewrite $3 * 3 ^ 3 = 81$

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =$

We simplify:

$\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =$

We apply distributive property:

$\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =$

Simplifying we finally have:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

Answer:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

5 0

3 years ago