<span>Answer: 17.8 cm
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<span>Explanation:
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<span>1) Since temperature is constant, you use Boyle's law:
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<span>PV = constant => P₁V₁ = P₂V₂
</span><span>=> V₁/V₂ = P₂/P₁</span>
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2) Since the ballon is spherical:
</span><span>V = (4/3)π(r)³</span>
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Therefore, V₁/V₂ = (r₁)³ / (r₂)³
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<span>3) Replacing in the equation V₁/V₂ = P₂/P₁:
</span><span><span>(r₁)³ / (r₂)³ </span>= P₂/P₁</span>
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And you can solve for r₂: (r₂)³ = (P₁/P₂) x (r₁)³
</span>(r₂)³ = (1.0 atm / 0.87 atm) x (17 cm)³ = 5,647.13 cm³
<span>
r₂ = 17.8 cm</span>
The motion of particles can be changed by the temperature you put it at.
In order to <span>decrease the pressure of a gas inside a closed cubical container, you need to decrease the temperature of the container. The volume of the system is rigid so it means volume is constant. By the ideal gas law, temperature and pressure are directly related. Increasing the temperature, increases the pressure and the opposite to happens.</span>
I believe the statement above is true. The stronger the wind, the larger the particles it erodes<span>. The stronger the wind, the larger the particles that are carried away.
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