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Nataly [62]
3 years ago
5

A tank contains 50 kg of salt and 1000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain

s from the tank at the rate 3 L/min. (a) What is the amount of salt in the tank initially
Chemistry
1 answer:
Studentka2010 [4]3 years ago
7 0

Answer : The amount of salt present in the tank initially are, 50 kg

Explanation : Given,

Mass of salt in the tank = 50 kg

Mass of water in the tank = 1000 L

Rate of flow of water in the tank = 6 L/min

Rate of flow of solution in the tank = 3 L/min

Now we have to determine the amount of salt present in the tank initially.

As per question, there are 50 kg of salt present in the tank initially in 1000 L of water.

Thus, the amount of salt present in the tank initially are, 50 kg

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Given the equation: HCl + Na2SO4 → NaCl + H2SO4, if you start with 8 moles of hydrochloric acid, how many grams of sulfuric acid
Simora [160]

Answer:

392g sulfuric acid are produced

Explanation:

Based on the balanced equation:

2HCl + Na2SO4 → 2NaCl + H2SO4

<em>2 moles of HCl produce 1 mole of sulfuric acid</em>

<em />

To solve the problem we need to find the moles of sulfuric acid produced based on the chemical equation. Then, using its molar mass -<em>Molar mass H2SO4 = 98g/mol- </em>we can find the mass of sulfuric acid produced:

<em>Moles sulfuric acid:</em>

8mol HCl * (1mol H2SO4 / 2mol HCl) = 4 mol H2SO4

<em>Mass sulfuric acid:</em>

4mol H2SO4 * (98g / mol) =

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sammy [17]

<u><em>Answer:</em></u>

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<u><em>Explanation:</em></u>

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