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3 years ago

the relationship between the heated air particles inside a hot air balloon and the cooler air outside the balloon?

2 answers:

6 0

The heated air temperature from inside the balloon more likely rises since it can't escape its trapped resulting in different density from the cooler air, the cooler air from the outside is a bit denser than the heated.

love history [14]3 years ago

3 0

Heating air under the balloon will cause the air inside to expand.

The air inside will have the same mass but more volume.

Heating the air under the balloon will cause the entire balloon to rise.

You might be interested in

uranium atoms each have 92 protons. how many protons does each u238 atom have? a. 92 b. 146 c. 238 d. 330

Brilliant_brown [7]

Number of protons as stated in the question = 92.

a. 92

4 0

3 years ago

Which of the following is not part of the proper protocol for using acids and bases?

Anni [7]

Answer:

B.Add acid to water,not water to acid

Explanation:

they should not be mixed

8 0

3 years ago

a balloon filled with a volume of 1.50 L is compressed to a volume of 0.50 L at a constant rate of temperature. if the initial p

Arisa [49]

Answer:

New pressure P2 = 4.95 atm

Explanation:

Given:

Old volume V1 = 1.50 L

New volume V2 = 0.50 L

Old pressure P1 = 1.65 atm

Find:

New pressure P2

Computation:

P1V1 = P2V2

So,

(1.50)(1.65) = (0.50)(P2)

New pressure P2 = 4.95 atm

5 0

3 years ago

A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica

Sladkaya [172]

Answer: The empirical formula for the given compound is $CH_5N$

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = $\frac{3.23}{3.23}=1$

For Hydrogen = $\frac{16.2}{3.23}=5.01\approx 5$

For Oxygen = $\frac{3.24}{3.23}=1.00\approx 1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is $C_1H_5N_1=CH_5N$

3 0

3 years ago

Y = 57.15 − 0.5 X If Y equals 5 , what is X ?<br><br> Then is Y=3, what is X?

Fiesta28 [93]

When y equals 5, x is 104.3

When y equals 3 then x is 108.3

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

$y = 57.15 - 0.5x$

<h3><u>If y equals 5 what is x ?</u></h3>

Substitute y = 5 in given expression

5 = 57.15 - 0.5(x)

5 = 57.15 - 0.5x

0.5x = 57.15 - 5

0.5x = 52.15

Divide both sides by 0.5

x = 104.3

Thus when y equals 5, x is 104.3

Substitute y = 3 in given expression

3 = 57.15 - 0.5(x)

3 = 57.15 - 0.5x

0.5x = 57.15 - 3

0.5x = 54.15

Divide both sides by 0.5

x = 108.3

Thus when y equals 3 then x is 108.3

7 0

3 years ago