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3 years ago

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What is a front? an air mass formed when cold air moves away from warm air the boundary between a warm air mass and a cold air m

ass the leading edge of a warm air mass the direction in which a rainstorm is moving

1 answer:

kompoz [17]3 years ago

3 0

A front is the boundary between a warm air mass and a cold air mass.

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How is n1 in the Rydberg equation related to the quantum number n in the Bohr model?How is n1 in the Rydberg equation related to

andre [41]

Ansddwdccwer:

ExplanationBecause:

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4 years ago

Identify the products formed in this Brønsted-Lowry reaction.<br><br> HPO2−4+NO−2↽−−⇀acid+base

klemol [59]

Answer: The products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Explanation:

According to Bronsted-Lowry, acids are the species which donate hydrogen ions to another specie in a chemical reaction.

Bases are the species which accept a hydrogen ion upon chemical reaction.

For example, $HPO^{2-}_{4} + NO^{-}_{2} \rightleftharpoons HNO_{2} + PO^{2-}_{4}$

Here, the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

Thus, we can conclude that the products formed in this Bronsted-Lowry reaction are $HNO_{2}$ and $PO^{2-}_{4}$ .

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3 years ago

What is a liquid mixture whose parts are evenly blended?.

Eva8 [605]

Answer:

A homogeneous mixture is a type of mixture in which the individual substances are evenly mixed.

Explanation:

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2 years ago

Select the correct answer. Given: 2Al + 6HCl → 2AlCl3 + 3H2 If the chemical reaction produces 129 grams of AlCl3, how many grams

ivann1987 [24]

The reaction produces 2.93 g H₂.

M_r: 133.34 2.016

2Al + 6HCl → 2AlCl₃ + 3H₂

<em>Moles of AlCl₃</em> = 129 g AlCl₃ × (1 mol AlCl₃/133.34 g AlCl₃) = 0.9675 mol AlCl₃

<em>Moles of H₂</em> = 0.9675 mol AlCl₃ × (3 mol H₂/2 mol AlCl₃) = 1.451 mol H₂

<em>Mass of H₂</em> = 1.451 mol H₂ × (2.016 g H₂/1 mol H₂) = 2.93 g H₂

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3 years ago

NEED HELP QUICKLY!!! How many moles are in each of the following?

oksano4ka [1.4K]

Answer: a. 0.26mol

b. 0.000479mol

c. 1.12mol

Explanation: Please see attachment for explanation

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3 years ago