We are given with a compound, Methane (CH4), with a molar
mass of 0.893 mol sample. We are tasked to solve for it's corresponding mass in
g. We need to solve first the molecular weight of Methane, that is
C=12 g/mol
H=1g/mol
CH4= 12 g/mol +1(4) g/mol = 16 g/mol
With 0.893 mol sample, its corresponding mass is
g CH4= 0.893 mol x 16g/mol =14.288 g
Therefore, the mass of methane is 14.288 g
Answer:
1. C
Carbon atoms
2. C
CH3CH2OH
3. C
extended structure
AND 4. B
One grey sphere, four white spheres, one red sphere
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Answer:
0.0977M is the concentration of the final solution
Explanation:
In a dilution process, to the original solution (Stock solution) you add more solvent in order to decrease its original concentration. To know how many times the solution was diluted you must find the dilution factor (Ratio between the initial and final volume). That is:
Intial Volume: 5.73mL
Final volume: 5.73mL + 20.26mL = 25.99mL
Dilution factor: 25.99mL / 5.73mL = 4.536 → 4.536 times the solution is diluted. The concentration of the diluted solution is:
0.443M / 4.536 =
<h3>0.0977M is the concentration of the final solution</h3>
It is amu or dalton both meet the same definition.
