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Tresset [83]
3 years ago
11

A student mixed some yellow sulfur powder with some iron filings. She was able to take the iron out of the sulfur by using a mag

net. She then remixed the iron and sulfur in a test tube and heated it. After it cooled, she removed the substance from the test tube but could not separate the iron from the sulfur using the magnet. Which type of change occurred in the material when it was heated?
Chemistry
1 answer:
Kay [80]3 years ago
8 0

Answer: Chemical change

Explanation:

Physical change is a change in which there is no rearrangement of atoms and thus no new substance is formed. There is only change in physical state of the substance. The change can be reversed using physical methods.

Chemical change is a change in which there is rearrangement of atoms and thus new substance is formed. There may or may not be a change in physical state. The change can only be reversed using chemical methods.

Thus when iron and sulfur are heated in a test tube, the chemical change occurs and thus lead to formation of new substances which could not be separated using magnet.

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(6.7*10^3)g/mol*L to kg/mol*dL
vodka [1.7K]
6.7× 10³ g/mol*L ×(1Kg÷1000g) × (1L÷10dL)=  0.67
7 0
3 years ago
Read 2 more answers
The value of the Solubility Product Constant for lead phosphate is ____________
emmasim [6.3K]

<u>Answer:</u> The reaction for the K_{sp} value of lead phosphate is given below and the value of solubility product for the same is 3.0\rightarrow 10^{-44}

<u>Explanation:</u>

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio. It is expressed as K_{sp}

The chemical formula of lead phosphate is Pb_3(PO_4)_2

The equation for the hydration of the lead phosphate is given as:

Pb_3(PO_4)_2(s)+H_2O(l)\rightarrow 3Pb^{2+}(aq.)+2PO_4^{3-}(aq.)

The solubility product of lead phosphate is 3.0\rightarrow 10^{-44}. This means that it is highly insoluble in water as the solubility product is very very low.

Hence, the reaction for the K_{sp} value of lead phosphate is given above and the value of solubility product for the same is 3.0\rightarrow 10^{-44}

4 0
3 years ago
Place these hydrocarbons in order of decreasing boiling point. Rank from highest to lowest boiling point. 1. Paraffin, C40Hg2 2.
lesya [120]

Answer:

Paraffin > Heptadecane > Hexane > 2,2-dimethylbutane > Propane

Explanation:

It must first be establish that all the molecules listed in the question are alkanes. For alkanes, the intermolecular forces between the molecules of alkanes increases with increasing molecular weight. This is as a result of increase in the surface area of the molecule. Increase in surface area implies a greater degree of dispersion forces.

This is the reason why high boiling points are observed for high molecular weight alkanes.

6 0
3 years ago
at a particular temperature, asample of pure water has a Kw of 1.7x10-12. what is the hydroxide concentration of this sample
Lena [83]

Answer:

Hydroxide concentration of the sample is 1.3x10⁻⁶M

Explanation:

The equilibrium constant of water, Kw, is:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Kw is defined as:

Kw = 1.7x10⁻¹² = [H⁺] [OH⁻]

As the sample is of pure water, both H⁺ and OH⁻ ions have the same concentration because come from the same equilibrium, that is:

[H⁺] = [OH⁻]

We can write the Kw expression:

1.7x10⁻¹² = [OH⁻] [OH⁻]

1.7x10⁻¹² = [OH⁻]²

1.3x10⁻⁶M = [OH⁻]

<h3>Hydroxide concentration of the sample is 1.3x10⁻⁶M</h3>
6 0
3 years ago
Calculate the amount of heat needed to melt of solid octane () and bring it to a temperature of . Round your answer to significa
elixir [45]

Answer:

85.0 kJ

Explanation:

Calculate the amount of heat needed to melt 160. g of solid octane (C8H18 ) and bring it to a temperature of 99.2 degrees c. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

To melt 160 g of octane and bring it's temperature to 99.2°C

(from literature)

Heat of fusion of Octane = 20.740 kJ/mol

Melting point of octane = -57°C

Boiling point of Octane = 125.6 °C

Molar mass of octane = 114.23 g/mol

Heat capacity of octane = 255.68 J/K.mol

So, it is evident that Octane is still a liquid at 99.2°C.

So, the required heat is the heat required to melt octane and raise the temperature of Octane liquid to 99.2°C

First, we convert the mass of octane given to number of moles as the heat parameters provided by literature are given in molar units.

Number of moles = (mass)/(Molar mass)

Number of moles of octane = (160/114.23) = 1.401 moles

Heat required to melt the octane = nL = (1.401×20.740) = 29.05674 kJ

Heat required to raise the temperature of already melted octane from its melting temperature of -57°C to 99.2°C

= nCΔT

n = 1.401 moles

C = 255.68 J/K.mol

ΔT = (99.2 - (-57)) = 156.2°C (same as a temperature difference of 156.2 K)

Heat required to raise the temperature of already melted octane from -57°C to 99.2°C

= (1.401×255.68×156.2)

= 55,952.04 J = 55.952 kJ

Total heat required to melt the 160 g of Octane and raise its temperature to 99.2°C

= 29.05674 + 55.952 = 85.01 kJ = 85.0 kJ

Hope this Helps!!!

8 0
3 years ago
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