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dem82 [27]
3 years ago
15

For each of the following pairs of elements, predict whether they will form a bond that is primarily ionic or one that is primar

ily covalent. Explain your answers.
lithium (Li) and oxygen (O) chlorine (Cl) and fluorine (F) calcium (Ca) and sulfur (S)
Chemistry
1 answer:
Archy [21]3 years ago
6 0
Types of Bonds can be predicted by calculating the difference in electronegativity.
If, Electronegativity difference is,

                 Less than 0.4 then it is Non Polar Covalent

                 Between 0.4 and 1.7 then it is Polar Covalent

 
                Greater than 1.7 then it is Ionic 

For Li and O,

                    E.N of Oxygen                 =   3.44

                    E.N of Lithium                  =   0.98
                                                             ________

                      E.N Difference                     2.46          (Ionic Bond)

For Cl and F,
                    E.N of Fluorine                 =   3.98

                    E.N of Chlorine                 =   3.16
                                                             ________

                      E.N Difference                     0.82   (Mildly Polar Covalent Bond)

For Ca and S,
                    E.N of Sulfur                   =   2.58

                    E.N of Calcium                =   1.00
                                                             ________

                      E.N Difference                   1.58          (Polar Covalent Bond)
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3 years ago
HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

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