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Svetlanka [38]
2 years ago
11

Please Help! How many molecules are in a 4.1 mole sample of CO?

Chemistry
1 answer:
SashulF [63]2 years ago
6 0

Answer:

16.34884*10^-23 g/ molecule.

Explanation:

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A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the perce
STALIN [3.7K]

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂

The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

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3 years ago
What is latice energy
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The energy required to separate a mole of an ionic solid into gaseous ions
3 0
3 years ago
What is an oxidation reaction? ​
kow [346]
<h3>Definition:</h3>
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  • It is a reaction is a type of chemical reaction that involves a transfer of electrons between two species.

  • Oxidation is gain of oxygen

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7 0
2 years ago
Describe the ammonium ion, NH4+, and the sulfate ion, SO42-. What compounds would these ions form with potassium and fluoride io
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<span>Cations mix with anions, so you know NH4+ won't mix with K+ and SO4(2-) won't miix with F-. For the reason that NH4+ and F- together have single charges, they'll mix in a 1:1 ratio, NH4F. There's two charges on SO4(2-), so it'll need two K+ to mix with, K2SO4.</span>
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The by-product of the chlorination of an alkane is​
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The by-product of the chlorination of an alkane is​  <u>HCl</u>

Explanation:

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  • Chlorination of alkane gives a mixture of different products.
  • When consider mechanism of alkanes chlorination, free radicals are formed during the reaction to keep the continuous reaction.
  • Different alkyl chloride compounds, extended carbon chains compounds and HCl are formed as products in product mixture.
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