1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetlanka [38]
2 years ago
11

Please Help! How many molecules are in a 4.1 mole sample of CO?

Chemistry
1 answer:
SashulF [63]2 years ago
6 0

Answer:

16.34884*10^-23 g/ molecule.

Explanation:

You might be interested in
Camphor, a white solid with a pleasant odor, is extracted from the roots, branches, and trunk of the camphor tree. Assume you di
katrin [286]

<u>Answer:</u> The molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

<u>Explanation:</u>

  • <u>Calculating the molarity of solution:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of camphor = 70.0 g

Molar mass of camphor = 152.2 g/mol

Volume of solution = 575 mL

Putting values in above equation, we get:

\text{Molarity of camphor}=\frac{70\times 1000}{152.2\times 575}\\\\\text{Molarity of camphor}=0.799M

  • <u>Calculating the molarity of solution:</u>

To calculate the mass of ethanol, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of ethanol = 0.785 g/mL

Volume of ethanol = 575 mL

Putting values in above equation, we get:

0.785g/mL=\frac{\text{Mass of ethanol}}{575mL}\\\\\text{Mass of ethanol}=(0.785g/mL\times 575mL)=451.38g

To calculate the molality of solution, we use the equation:

\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

m_{solute} = Given mass of solute (camphor) = 70 g

M_{solute} = Molar mass of solute (camphor) = 152.2  g/mol

W_{solvent} = Mass of solvent (ethanol) = 451.38 g

Putting values in above equation, we get:

\text{Molality of camphor}=\frac{70\times 1000}{152.2\times 451.38}\\\\\text{Molality of camphor}=1.02m

  • <u>Calculating the mole fraction of camphor:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

<u>For camphor:</u>

Given mass of camphor = 70 g

Molar mass of camphor = 152.2 g/mol

Putting values in equation 1, we get:

\text{Moles of camphor}=\frac{70g}{152.2g/mol}=0.459mol

<u>For ethanol:</u>

Given mass of ethanol = 451.38 g

Molar mass of ethanol = 46 g/mol

Putting values in equation 1, we get:

\text{Moles of ethanol}=\frac{451.38g}{46g/mol}=9.813mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

Moles of camphor = 0.459 moles

Total moles = [0.459 + 9.813] = 10.272 moles

Putting values in above equation, we get:

\chi_{(camphor)}=\frac{0.459}{10.272}=0.045\

  • <u>Calculating the mass percent of camphor:</u>

To calculate the mass percentage of camphor in solution, we use the equation:

\text{Mass percent of camphor}=\frac{\text{Mass of camphor}}{\text{Mass of solution}}\times 100

Mass of camphor = 70 g

Mass of solution = [70 + 451.38] = 521.38 g

Putting values in above equation, we get:

\text{Mass percent of camphor}=\frac{70g}{521.38g}\times 100=13.43\%

Hence, the molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

3 0
3 years ago
Need help asap please!
Andrei [34K]

Answer:

B

Explanation:

because polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.

4 0
2 years ago
As the Amplitude of the wave decreases what be does the frequency do​
Alexxx [7]

Answer: pic of the test

Explanation:

4 0
2 years ago
Balance the following equation. Then determine the ratio for the products KCl and O2 generated during the decomposition of potas
drek231 [11]
The answer is 2:3 for plato users

6 0
2 years ago
Read 2 more answers
By studying the distribution of different types of fossils, geologists have determined that some plates have traveled great dist
WITCHER [35]

Answer:

A. Fossils of organisms that lived in warm climates have been found in arctic environments.

Explanation:

One of the logic used by Geologists to justify plate movement over a region of space is that the fossils of organisms that lived in warm climates have been found in arctic environments.

  • this is as a result of plate tectonics.
  • organisms that are well adapted to warm climates in times past have their relics preserved as fossils.
  • their fossils are no found today around the arctic environment which are cold
  • this suggests that the plate must have drifted or moved
6 0
2 years ago
Other questions:
  • Convert 7.680 moles of PtSe to grams
    15·1 answer
  • Oxygen get stable configuration by ____________two electrons
    6·2 answers
  • How many electromagnetic forces exist?
    10·2 answers
  • Helppppp asappp idkkkll how to do thisssss!!!
    14·1 answer
  • Which best describes most covalent compounds? A.soft B.brittle C.cold D.warm​
    11·2 answers
  • ANSWER FAST PLZ 25 POINTS!!!!!!!!!!!!!!!
    9·1 answer
  • Why is the Earth's hydrosphere (oceans) made up of mostly hydrogen<br> and oxygen? *
    15·1 answer
  • List two adaptations the cave glow worm has for capturing prey in a cave
    10·1 answer
  • Scientific hypotheses differ from scientific theories in that they are
    6·1 answer
  • Which of the following lists contain ONLY metals?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!