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vovikov84 [41]
3 years ago
11

Stearic acid (C18H36O2) is a fatty acid, a molecule with a long hydrocarbon chain and an organic acid group (COOH) at the end. I

t is used to make cosmetics, ointments, soaps, and candles and is found in animal tissue as part of many saturated fats. In fact, when you eat meat, you are ingesting some fats containing stearic acid. ( of C18H36O2 = –948 kJ/mol, CO2=-393.5kJ/mol, H2O=-241.826kJ/mol).
Calculate the heat (q) released in kcal when 2.831 g of stearic acid is burned completely.
Chemistry
1 answer:
aev [14]3 years ago
6 0

The molar mass of stearic acid is 18*AC+36*AH+2*AO=18*12+36*1+16*2=284g/mol.

n=m/M=2.831/284=0.01 moles

C18H36O2+27O2-->18CO2+18H2O

we have 18*0.01=0.18 moles of CO2

18*0.01=0.18 moles of H2O

0.01*948=9.48kJ from stearic acid

0.18*393.5=70.83kJ from CO2

0.18*241.826=43.52kJ from H2O

9.48+70.83+43.52=123.83kJ

123.83*4.184=518.10kcal

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3 years ago
A sample of 67 G of kno2 is dissolved to make 1 L of solution what is the molarity of the solution?
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Answer:

Molarity = 0.79 M

Explanation:

Given data:

Mass of KNO₂ = 67 g

Volume of solution = 1 L

Molarity of solution = ?

Solution:

First of all we will calculate the number of moles.

<em>Number of moles = mass/ molar mass</em>

Number of moles = 67 g / 85.10379 g/mol

Number of moles = 0.79 mol

Molarity:

Molarity = number of moles / volume in L

Molarity =  0.79 mol/1 L

Molarity = 0.79 M

8 0
3 years ago
Suppose now that you wanted to determine the density of a small crystal to confirm that it is graphite. From the literature, you
kirza4 [7]

Answer:

The volume of first and second compound are 9.15 ml and 10.85 ml.

Explanation:

Given that,

Density of graphite = 2.25 g/cm³

Volume of mixture = 20.0 mL

Density of first compound = 1.492 g/ml

Density of second compound = 2.890 g/ml

Let the volume of first mixture = x

The volume of second mixture = (20-x)....(I)

We need to calculate the volume of first compound

Using formula of  density of mixture

\rho=\dfrac{V_{1}\rho_{1}+V_{2}\rho_{2}}{V_{1}+V_{2}}

Where, V_{1} = volume of first compound

V_{2} = volume of second compound

\rho_{1} =density of first compound

\rho_{1} = density of first compound

Put the volume into the formula

2.25=\dfrac{x\times1.492+(20-x)\times2.890}{x+20-x}

45=1.492x+57.8-2.890x

45-57.8=1.492x-2.890x

12.8=1.398x

x=\dfrac{12.8}{1.398}

x=9.15\ ml

We need to calculate the volume of second compound

Using equation (I)

V_{2}=20-x

Put the value of x

V_{2}=20-9.15

V_{2}=10.85\ ml

Hence, The volume of first and second compound are 9.15 ml and 10.85 ml.

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Answer:

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4 years ago
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