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DochEvi [55]
3 years ago
12

HELP.

Chemistry
1 answer:
Kamila [148]3 years ago
4 0

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

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How many atoms in 2.25 mol of O2
Luden [163]

Answer:

1 molecule of oxygen has 2 atoms.

So 2,25 molecules of oxygen have 2 x 2,25 atoms.

2 x 2,25 = 4,5 atoms

There are 4,5 atoms in 2,25 molecules oxygen.

3 0
3 years ago
Consider the resonance structures for the carbonate ion. carbonate is a carbon double bonded to an oxygen with two lone pairs an
Bumek [7]

Answer:

The correct answers are: <u>Each oxygen of carbonate ion has -2/3 or -0.67 charge.</u>

<u>Bond order of each carbon‑oxygen bond in the carbonate ion</u> = <u>1.33</u>

Explanation:

The carbonate ion (CO₃²⁻) is an organic compound, in which a carbon atom is covalently bonded to three oxygen atoms. The net formal charge on a carbonate ion is −2.

The carbonate ion is <u>resonance stabilized</u> and has three equivalent resonating structures, which exhibits that all the three carbon-oxygen bonds in a carbonate ion are equivalent.

In the resonance hybrid of carbonate ion,<u> the negative charge is equally delocalized on all the three oxygen atoms. </u>

<u>Thus, each bonded oxygen has -2/3 or -0.67 charge.</u>

<u />

In a carbonate ion there is one double bond oxygen (C=O) and two single bonded oxygen (C-O). Bond order of 1 C=O is 2 and bond order of C-O is 1.

∴ <u>Bond order</u> = sum of all bond orders ÷ number of bonding groups = (2+1+1) ÷ 3 = <u>1.33</u>

8 0
3 years ago
Balance the following redox equation, using half-reactions. Assume that the reaction occurs in an aqueous solution.
anastassius [24]
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Reduction half reaction: 
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5 0
3 years ago
7. A student titrated a 15.00-mL sample of a solution containing a weak, monoprotic acid with NaOH. The titration required 17.73
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Answer:  The concentration of the weak acid in the sample is 0.1224 M

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HA+NaOH\rightarrow NaA+H_2O

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HA

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?\\V_1=15.00mL\\n_2=1\\M_2=0.1036M\\V_2=17.73mL

Putting values in above equation, we get:

1\times M_1\times 15.00=1\times 0.1036\times 17.73\\\\M_1=0.1224

Thus the concentration (in M) of the weak acid in the sample is 0.1224

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<span>
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<span>
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3 0
3 years ago
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