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kozerog [31]
3 years ago
10

Compare and contrast the thermosphere with the troposphere

Physics
1 answer:
9966 [12]3 years ago
5 0
The troposhere is the lowest layer of the Earth's atmosphere and the thermosphere is the second, above the mesosphere and below the exosphere. 
Thermosphere is the largest of all the layers. It is within the thermosphere that ultraradiation causes ionization. 
The troposhere is where 99% of the water vapor and aerosols are found. It is denser than the layers above it because of the weight compressing it. The troposphere as well contains approximately 75% of the mass of the atmosphere. Most of the world's weather takes place in the troposhere.
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i would say 20J

Explanation:

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True

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A car accelerates from 10 km/hr to 50 km/hr in 8 seconds. What is the acceleration?
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A hiker climbs a mountain. Starting at the base of the mountain, he first moved up 520m at a 32.0 degree angle. What is the fina
balu736 [363]

Answer:

\displaystyle \vec{d}=

Explanation:

<u>Displacement Vector</u>

Suppose an object is located at a position  

\displaystyle P_1(x_1,y_1)

and then moves at another position at

\displaystyle P_2(x_2,y_2)

The displacement vector is directed from the first to the second position and can be found as

\displaystyle \vec{d}=

If the position is given as magnitude-angle data ( z , α), we can compute its rectangular components as

\displaystyle x=z\ cos\alpha

\displaystyle y=z\ sin\alpha

The question describes the situation where the initial point is the base of the mountain, where both components are zero

\displaystyle P_1(0,0)

The final point is given as a 520 m distance and a 32-degree angle, so  

\displaystyle x_2=520\ cos32^o= 440.99\ m

\displaystyle y_2=520\ sin32^o=275.6\ m

The displacement is

\displaystyle \vec{d}=

5 0
3 years ago
A gun fires a bullet vertically into a 1.40-kg block of wood at rest on a thin horizontal sheet. If the bullet has a mass of 22.
Bogdan [553]

Answer:

A. 1.172 metres

B. 6.82 Ns

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The 1.40 kg block is at rest so velocity is zero and has no momentum.

The bullet of mass 22 g = 0.022 kg with velocity of 310 m/s

Momentum = 310*0.022

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V = 6.82/1.422

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How high the block will rise after the bullet is embedded is given by

H = (U²Sin²tita)/2g

Where tita is 90°

H = (4.796² * sin²(90))/(2*9.81)

H =( 23.001616*1)/19.62

H = 1.172 metres

6 0
4 years ago
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