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kozerog [31]
4 years ago
10

Compare and contrast the thermosphere with the troposphere

Physics
1 answer:
9966 [12]4 years ago
5 0
The troposhere is the lowest layer of the Earth's atmosphere and the thermosphere is the second, above the mesosphere and below the exosphere. 
Thermosphere is the largest of all the layers. It is within the thermosphere that ultraradiation causes ionization. 
The troposhere is where 99% of the water vapor and aerosols are found. It is denser than the layers above it because of the weight compressing it. The troposphere as well contains approximately 75% of the mass of the atmosphere. Most of the world's weather takes place in the troposhere.
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How much energy, in joules, is released when 17 kilograms of granite is cooled from 45°C to 21°C?
zepelin [54]
The final answer is -322, 320 Joules. The solution for the problem is:

The equation that must be used in this problem is:

U = mCp(Tf-Ti)

where:
U = energy released or absorbed in Joules
m = mass in kg
Cp = specific heat of material in J/kg-C
Tf = final temperature, C
Ti = initial temperature, C

Looking up the Cp of granite gives a value of 790 J/kg-C.

U = 17kg (790 J/kg-C) (21-45)
<span>U = - 322, 320 Joules (negative means heat is released)</span>
4 0
4 years ago
Read 2 more answers
Air resistance is a nonconservative force. It always opposes the motion of an object. An airplane flies from New York to Atlanta
LenKa [72]

Answer:

c) is negative

Explanation:

As we know that work done by a force is the product of force and displacement vector.

W= F.d

F= Force

d= displacement

The work done by friction force always negative because it try to oppose the motion and act opposite to the direction of displacement.So the work done by air resistance is negative.

c) is negative

8 0
4 years ago
List three additional real world examples that show work being done.
ser-zykov [4K]

The real world examples that I can give is the everyday things that we do and some of these are:

I am walking to the end of the room holding three textbooks.


Playing tug of war with friends.


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7 0
4 years ago
Calculate the pressure when a force of 200N acts on an area of 0.05cm2<br> .
deff fn [24]

FORCE ACTING ON THE BODY , F = 200N

AREA ON WHICH THE FORCE IS ACTING , A = 0.05 CM²

= 0.05*(10⁻²)

= 0.05*10⁻² M²

TO CONVERT CM TO M * BY 10⁻²

PRESSURE = FORCE / AREA

PRESSURE = 200/0.05*10⁻⁴

= 200*10⁴/0.05

= 200*10⁴*10²/5

= 20*10⁵/5

= 4*10⁵ N/M².

HOPE THIS HELPS.

4 0
2 years ago
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