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3 years ago

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A 2.0 g identification reflector glued to one end of a helicopter rotor is spinning at a tangential velocity of 2093 m/s. The re

flector takes 0.03 s to complete one revolution. Find the radius of the rotor.

1 answer:

katrin2010 [14]3 years ago

7 0

372863 juusnjus bhhhanbubhgajhus

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xIn the reaction A B + C + heat, ______. there is a net input of energy the potential energy of the products is greater than tha

kow [346]

Answer: Option (d) is the correct answer.

Explanation:

A chemical reaction in which heat energy is liberated is known as an exothermic reaction.

For example, $A \rightarrow B + C + Heat$

In an exothermic reaction, energy of reactants is more than the energy of products.

This means that potential energy of products is less than the potential energy of reactants.

Thus, we can conclude that in the reaction $A \rightarrow B + C + heat$ , the potential energy of the products is less than that of the reactant.

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2 years ago

I NEED HELP ASAP! PLSSSSSSSSSSSSSSSSSSS

OleMash [197]

I’m pretty sure

Part 1; C
Part 2; C

Not 100% sure tho :)

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3 years ago

Will a solid metal sphere hold a larger elaectric charge than a hollow sphere of the same diameter?Where does the charge reside

melomori [17]

The answer would be no. Both will have same charge, in both caes charge will reside on surface. In case of solid sphere it will be distributed evenly throughout. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

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3 years ago

Theory that earth processes occurring today are similar to those that occurred in the past whats the word

Studentka2010 [4]

Its uniformitarianism.

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3 years ago

Car A (1750 kg) is travelling due south and car B (1450 kg) is travelling due east. They reach the same intersection at the same

Contact [7]

Consider the east-west direction along x-axis and north-south direction along y-axis. In unit vector notation, velocities can be given as

$\underset{V_{A}}{\rightarrow}$ = velocity of car A before collision = 0 i - $V_{A}$ j

$\underset{V_{B}}{\rightarrow}$ = velocity of car B before collision = $V_{B}$ i + 0 j

$\underset{V_{AB}}{\rightarrow}$ = velocity of combination after collision = (35.8 Cos31.6) i - (35.8 Sin31.6) j = 30.5 i - 18.8 j

$M_{A}$ = mass of car A = 1750 kg

$M_{B}$ = mass of car B = 1450 kg

Using conservation of momentum

$M_{A}$ $\underset{V_{A}}{\rightarrow}$ + $M_{B}$ $\underset{V_{B}}{\rightarrow}$ = ( $M_{A}$ + $M_{B}$ ) ( $\underset{V_{AB}}{\rightarrow}$ )

(1750) (0 i - $V_{A}$ j) + (1450) ( $V_{B}$ i + 0 j) = (1750 + 1450) (30.5 i - 18.8 j)

(1450) $V_{B}$ i - (1750) $V_{A}$ j = 97600 i - 60160 j

Comparing the coefficient of "i" and "j" both side

(1450) $V_{B}$ = 97600 and - (1750) $V_{A}$ = - 60160

$V_{B}$ = 67.3 km/h and $V_{A}$ = 34.4 km/

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3 years ago