Given:
p = 20% = 0.2, sample proportion
n = 5000, sample size.
Confidence level = 95%
The confidence interval is
(p - 1.96k, p + 1.96k)
where
Therefore the 95% confidence interval is
(0.1943, 0.2057) = (19.4%, 20.6%)
Answer: The 95% confidence interval is (19.4%, 20.6%)
Answer:
// C++ Program to arithmetic operationf on 2 Numbers using Recursion
// Comments are used for explanatory purpose
#include <bits/stdc++.h>
using namespace std;
// add10 recursive function to perform arithmetic operations
int add10(int m, int n)
{
return (m + product(n, 10)); //Result of m + n * 10
return 0;
}
// Main Methods Starts here
int main()
{
int m, n; // 2 Variables m and n declared as integer
cin>>m; // accept input for m
cin>>n; // accept input for n
cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n
return 0;
}
Answer:
The answer is 146
Step-by-step explanation:
5n-2=n+18
Move n to the other side
Sign changes from +n to -n
5n-n-2= n-n+18
5n-n-2= 18
4n-2= 18
Move -2 to the other side
Sign changes from -2 to +2
4n-2+2= 18+2
4n= 18+2
4n= 20
Divide by 4 for both sides
4n/4= 20/4
Answer: n=5
