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Serggg [28]
3 years ago
12

Suppose that 3 PLS HELP NEED ANSWER

Mathematics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:with?

Step-by-step explanation:

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clara is playing a game where you score -8 points each time you guess the correct answer. the goal is to get the lowest score. t
Lina20 [59]

Answer:

272

Step-by-step explanation:

-8--280=272

7 0
3 years ago
ASAP NEED HELP ON MY MATH RETAKE I NEED HELP PLZZZ IM BEGGING YALL
Sindrei [870]

Answer:

B) There tends to be a linear association between variables

c) the data includes one or more outliers

8 0
3 years ago
ILL GIVE BRAINLIEST<br><br> Combine like terms.<br> 4x – 7y + 2x – 4 = [ ? ]x + [ ]y + [ ]
maxonik [38]

Answer:

[6x] + [-7y] + [-4]

Step-by-step explanation:

There are only two like terms in this expression "4x" and "2x." Since they are like terms we can combine them by adding the coefficients and keeping the variable attached. Therefore we can combine 4x and 2x into 6x. Since there are no more like terms, this expression can be simplified to 6x - 7y - 4.

7 0
3 years ago
Read 2 more answers
Which answer best describes the complex zeros of the polynomial function?
marysya [2.9K]

<u>Answer-</u>

<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>

<u>Solution-</u>

The given polynomial is,

f(x)=x^3-x^2+6x-6

The zeros of the polynomials are,

\Rightarrow f(x)=0

\Rightarrow x^3-x^2+6x-6=0

\Rightarrow x^2(x-1)+6(x-1)=0

\Rightarrow (x^2+6)(x-1)=0

\Rightarrow (x^2+6)=0,(x-1)=0

\Rightarrow x=\sqrt{-6},\ x=1

\Rightarrow x=1,\ \pm \sqrt6i

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

3 0
3 years ago
Please help me with #7
Dominik [7]

Step-by-step answer:

This is a regular heptagon, means it has 7 <em>congruent</em> sides and 7 <em>congruent </em>vertex angles.

To work with polygons, there is a very important piece of information that you must know to solve the majority of related problems.

This is:

sum of exterior angles of polygons = 360 degrees.

If you don't remember the 360 degrees, think of the sum of exterior angles of an equilateral triangle, which is 3*(180-60)=3*120=360!  It works!

For a regular heptagon, c = 360/7=51.43 degrees approx.

This means that each vertex angle measures

vertex angle = 180-c

So since 2d+the vertex angle = 360, we have

2d+(180-c)=360

solve for d:

2d=360-(180-c)=180+c

d=(180+c)/2=90+c/2=115.71 degrees. (approx.)

8 0
3 years ago
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