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3 years ago

13

Can you ever use a calculator to determine if a number is rational or irrational? Explain.

2 answers:

Setler79 [48]3 years ago

8 0

I would say no' as calculators were designed to give us approximate answers when dealing with irrational numbers.
It would be hard to guess whether a large number produced by a calculator is irrational or not given that fact that many rational numbers can be incredibly long.

Nataly [62]3 years ago

3 0

Irrational cannot be represented as a fraction. so your answer is yes.

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The graph of an equation with a negative discrimiant always has which characteristic?

Leokris [45]

Answer is A. no x-intercept

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4 years ago

Find the volume of a sphere whose surface area is 1256 sq.cm (Take π = 3.14)<br>

Alekssandra [29.7K]

Curved surface area of a sphere =1256 cm

2

We know that, Curved surface area of a spehre =4πr

2

⟹1256=4×3.14×r

2

⟹r

2

=

4×3.14

1256

⟹r

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=100

∴r=10 cm

Hence, the answer is 10 cm.

4186.66666666 volume of sphere

6 0

3 years ago

Read 2 more answers

1. 7:4 = 21:x; what is the value of x?<br> A. 12<br> B. 10<br> C. 8<br> D. 6<br> E. 4<br> 8.

Soloha48 [4]

Answer:

x = 12

I hope it's helps you

8 0

3 years ago

Im giving 30 points pls help

gayaneshka [121]

Step-by-step explanation:

Pathagory and Theorem

a^2+b^2=c^2

(x-3)^2+(x-4)^2=6^2

expand:

2x^2-14x+25=36

2x^2-14x-11=0

x=(\sqrt{71}+7)/2

perimeter=(x-3)+(x-4)+6=2x-1

insert the value for x into 2x-1

$\sqrt{71}$ +6=perimeter

Hope that helps :)

7 0

3 years ago

Read 2 more answers

A bag contains 4 white, 3 blue, and 6 red marbles. A marble is drawn from the bag, replaced, and another marble is drawn. Find t

PilotLPTM [1.2K]

First find the probability of each color being drawn.

We need to find the total number of marbles first.

4 + 3 + 6 = 13

So everything will be over 13.

Probability of a white marble being drawn --> $\frac{4}{13}$

Probability of a blue marble being drawn --> $\frac{3}{13}$

Probability of a red marble being drawn --> $\frac{6}{13}$

Now to find the probabilities of more than one being drawn, we can multiply.

Part a :

$\frac{6}{13}*\frac{6}{13}=\frac{36}{169}$

Part b :

$\frac{3}{13}*\frac{3}{13}=\frac{9}{169}$

Part c :

$\frac{6}{13}*\frac{3}{13}=\frac{18}{169}$

Part d :

$\frac{7}{13}*\frac{7}{13}=\frac{49}{169}$

5 0

3 years ago