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Kaylis [27]
4 years ago
8

A car drives horizontally off a 73-m-high cliff at a speed of 27 m/s. Ignore air resistance. How long will it take the car to hi

t the ground?
Physics
1 answer:
anygoal [31]4 years ago
3 0

At the edge of the cliff, the speed of the car will have two components. The x-component, horizontal, is equal to 27 m/s while the y-component, vertical, is equal to zero. With this, the car is seemingly in free-fall.

 The equation that would allow us to answer the question above is,

    d = (V₀)t + 0.5gt²

where d is distance, V₀ is the initial velocity, g is the acceleration due to gravity and t is the time. Substituting the known values,

    73 = (0)(t) + 0.5(9.8 m/s²)(t²)

Vo  equals zero because we only consider the y-component of the vector. Solving for the value of t will give us an answer of 3.86 s.

Answer: 3.86 seconds

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On planet X, an object weighs 7.04 N. Onplanet B where the magnitude of the free-fallacceleration is 1.91g(whereg= 9.8 m/s2isthe
timurjin [86]
<h2>Mass of object in Earth is 1.37 kg</h2>

Explanation:

On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.

We have

           Weight = Mass x Acceleration due to gravity

On planet B

           25.74 = Mass x 1.91 g

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Mass of object in Earth = Mass of object in Planet B

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Explanation:

The law of conservation of momentum states that the total momentum of an isolated system is constant.

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p_i = p_f

But the initial momentum is zero, because at the beginning both the cannon and the projectile are at rest:

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So the final momentum, which is sum of the momentum of the cannon and of the projectile, must also be zero:

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