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Dimas [21]
2 years ago
13

2. What is the energy that comes from heat?

Physics
2 answers:
MrRissso [65]2 years ago
8 0

Answer:

exothermic

Explanation:

fgiga [73]2 years ago
7 0
Answer is

B. Exothermic
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A body of mass 3.0Kg is acted upon by a force of 24N, if the frictional force on the body is 13N.Calculate the acceleration of t
lisabon 2012 [21]

Answer:

Fnet=ma

24-13=3a

11/3=a

a=3.6m/s2

4 0
2 years ago
An amoeba has 1.00 x 1016 protons and a net charge of 0.300 pC. Assuming there are 1.88 x 106 fewer electrons than protons, If y
Xelga [282]

Answer:

The fraction of the protons would have no electrons =1.88\times 10^{-10}

Explanation:

We are given that

Amoeba has total number of protons=1.00\times 10^{16}

Net charge, Q=0.300pC

Electrons are fewer than protons=1.88\times 10^6

We have to find the fraction of protons would have no electrons.

The fraction of the protons would have no electrons

=\frac{Fewer\;electrons}{Total\;protons}

The fraction of the protons would have no electrons

=\frac{1.88\times 10^{6}}{1.00\times 10^{16}}

=1.88\times 10^{-10}

Hence, the fraction of the protons would have no electrons =1.88\times 10^{-10}

6 0
2 years ago
5. Radioactive isotopes can be used to find the age of rocks, fossils, or other artifacts. Carbon 14 has a half-life of 5,730 ye
horrorfan [7]

Answer:

A

Explanation:

Cuz i smart

7 0
3 years ago
The isomerization of cyclopropane to form propene is a first-order reaction. At 760 K, 85% of a sample of cyclopropane changes t
Nataliya [291]

Answer:

so rate constant  is 4.00 x 10^-4 s^{-1}

Explanation:

Given data

first-order reactions

85% of a sample

changes to propene t =  79.0 min

to find out

rate constant

solution

we know that

first order reaction are

ln [A]/[A]0 = -kt

here [A]0 = 1 and (85%) = 0.85 has change to propene

so that [A] = 1 - 0.85 = 0.15.

that why

[A] / [A]0= 0.15 / 1

[A] / [A]0 = 0.15

here t = (79) × (60s/min) = 4740 s  

so

k = - {ln[A]/[A]0} / t

k = -ln 0.15 / 4740

k = 4.00 x 10^-4 s^{-1}

so rate constant  is 4.00 x 10^-4 s^{-1}

3 0
2 years ago
A girl rolls a basketball across a basketball court. The ball slowly decelerates at a rate of -0.20m/s^2. If the initial velocit
Dafna1 [17]

By equation of motion :

2as=v^2-u^2\\\\s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{0^2-2^2}{2\times( -0.2)}\\\\s=10\ m

Now, it is given that it stops after 5 seconds of motion and time at that point is 12:00.

So, time when it started is 11 : 59 : 55.

Therefore, distance travelled is 10 m.

Hence, this is the required solution.

7 0
3 years ago
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