A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.
F(1) = 240 +210
F(2) = 240 +2(210)
F(3) = 240+3(210)
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F(x)= 240 +210x.
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A.9
B.12
C.2
D.5
E.7.4
F.5 2/3 or 5.6666
Answer:
y = 3/4 + 7
Step-by-step explanation:
you must put the equation into the form of y = mx + b
add 6x to both sides and put it in front of the 56
8y = 6x + 56
y must be by itself by x does not so we divide everything by 8
y = 6/8x + 7
we must simplify the fraction 6/8
y = 3/4x + 7
