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2 years ago

What type of chemical reaction is the following: Ag2O ➜Ag + O2

Chemistry

1 answer:

DochEvi [55]2 years ago

8 0

Answer:

Decomposition reaction

Explanation:

2Ag₂O => 4Ag + O₂

As silver oxide is split into silver metal and oxygen gas, it can be classified as decomposition reaction.

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Which one of the samples contains the most molecules?

Alex

Answer: D is right

Explanation: One mole contains 6.0225 ·10^23 molecules

Despite of the substance

7 0

3 years ago

For each molecule of propane (C3H8) that burns, three molecules of carbon dioxide are produced (3CO2). How many total oxygen ato

ELEN [110]

Given the criteria, there are six because there are three Carbon dioxide molecules and di means two; so two times three us six. But if u look at the whole reaction *pictured below* u will see that in the entire reaction there are 10 Oxygen reacting through the whole thing.
*the triangle is the Greek letter delta and it symbolizes heat in a reaction.

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3 years ago

A balloon inflated in a room at 300 ºC has a volume of 7.0 L. The balloon is then cooled to a temperature of 25.0 ºC. What is th

QveST [7]

Answer:

$\huge\boxed{\sf V_2 =3.64 \ L}$

Explanation:

Given Data:

Initial Volume = $V_{1}$ = 7.0 L

Initial Temperature = $T_{2}$ = 300 °C + 273 = 573 K

Final Temperature = $T_{2}$ = 25.0 °C + 273 = 298 K

Required:

Final Volume = $V_{2}$ = ?

Formula:

$\displaystyle \frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ [Charles Law]

Solution:

Put the givens

$\displaystyle \frac{7}{573 } =\frac{V_2}{298} \\\\0.01 = \frac{V_2}{298} \\\\\times 298 \ to \ both \ sides\\\\0.01 \times 298 = V_2\\\\3.64 \ L =V_2\\\\\boxed{V_2 =3.64 \ L}\\\\\rule[225]{225}{2}$

8 0

2 years ago

In what kind of reaction does one element replace a similar element in a compound?

andriy [413]

I believe what you are talking about is the synthesis reaction

4 0

4 years ago

A 150 mL of oxygen gas is collected over water at 20 °C and 758 torr. What volume will the same sample of oxygen occupy at STP w

Stella [2.4K]

Answer:

The volume would be; 136.17 ml

Explanation:

Volume V1 = 150 mL

Temperature T1 = 20°C + 273 = 293 K

Pressure P1 = 758 - 17.54 = 740.46 torr

At STP;

Volume V2 = ?

Pressure P2 = 760 torr

Temperature T2 = 273 K

Using the general gas equation;

P1V1 / T1 = P2V2 / T2

Making V2 subject of formulae;

V2 = P1V1T2 / T1P2

Inserting the values we have;

V2 = 740.46 * 150 * 273 / 293 * 760

V2 = 136.17 ml

3 0

3 years ago