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2 years ago

ANSWER FAST!!

Chemistry

1 answer:

belka [17]2 years ago

4 0

Answer: 800 mL of methyl alcohol should be added to 200 ml of water to make this solution.

Explanation:

Volume of the methyl alcohol = x

Volume of water = y = 200 mL

Volume of the solution ,V = x + y

Volume percentage of solution = 80%

x = 800 mL

800 mL of methyl alcohol should be added to 200 ml of water to make this solution.

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Gas and oxygen gas are the _______.

stiv31 [10]

i think it is Synthesis Reaction because in a synthesis reaction one or more simple substances combine to form a more complex substance.

If there is two or more reactions yilding one product is another way to identify a synthesis reaction.

For the chemical equation for this synthesis reaction really looks like:

reactant +reactant = product

if im wrong correct me but have a blessed day/night

4 0

2 years ago

what is ( H+) and (OH-) in a healthy person's blood that has a PH of 7.50 assume that the temperature of the blood is 298 K.

AlekseyPX

pH = - log [H⁺]

pH = 7.5

$\tt [H^+]=10^{-7.5}=3.16\times 10^{-8}$

pH + pOH = 14

7.5 + pOH = 14

pOH = 6.5

$\tt [OH^-]=10^{-6.5}=3.16\times 10^{-7}$

5 0

1 year ago

Can you guess this place? In Arizona.

Temka [501]

Answer:

a high school classroom?

Explanation:

a high school classroom prob chemistry

8 0

1 year ago

Read 2 more answers

Help Pls!

Salsk061 [2.6K]

Answer:

d= 50.23 g/cm³

Explanation:

Given data:

radius = 137.9 pm

mass is = 5.5 × 10−22 g

density = ?

Solution:

volume of sphere= 4/3π r³

First of all we calculate the volume:

v= 4/3π r3

v= 1.33× 3.14× (137.9)³

v= 1.33 × 3.14 × 2622362.939 pm³

v= 1.095 × 10∧7 pm³

v= 1.095 × 10∧-23 cm³

Formula:

Density:

d=m/v

d= 5.5 × 10−22 g/ 1.095 × 10∧-23 cm³

d= 5.023 × 10∧+1 g/cm³

d= 50.23 g/cm³

8 0

2 years ago

A 2.89 g sample of a metal chloride, MCl2, is dissolved in water and treated with excess aqueous silver nitrate. The silver chlo

dsp73

Answer:

58.0 g/mol

Explanation:

The reaction that takes place is:

MCl₂ + 2AgNO₃ → 2AgCl + M(NO₃)₂

First we calculate how many moles of silver chloride were produced, using its molar mass:

6.41 g AgCl ÷ 143.32 g/mol = 0.0447 mol AgCl

Then we convert AgCl moles into MCl₂ moles, using the stoichiometric ratio:

0.0447 mol AgCl * $\frac{1molMCl_2}{2molAgCl}$ = 0.0224 mol MCl₂

Now we calculate the molar mass of MCl₂, using the original mass of the sample:

2.86 g / 0.0224 mol = 127.68 g/mol

We can write the molar mass of MCl₂ as:

Molar Mass MCl₂ = Molar Mass of M + (Molar Mass of Cl)*2

127.68 g/mol = Molar Mass of M + (35.45 g/mol)*2

Finally we calculate the molar mass of M:

Molar Mass of M = 57 g/mol

The closest option is 58.0 g/mol.

6 0

2 years ago