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LenaWriter [7]
3 years ago
7

An element's atomic number is the _____?

Chemistry
2 answers:
g100num [7]3 years ago
6 0
Number<span> of protons found in the nucleus of an </span>atom<span>.</span>
pantera1 [17]3 years ago
6 0
An element's atomic number is the protons with positive charge from the nucleus atom.

Hope it helped you.

-Charlie
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The name of CuO is --
Vesnalui [34]

The name is Copper(II) Oxide and/or Cupric Oxide.

Cu is Copper and O is Oxygen.

Usually when the Oxygen ion is placed after another, it's name is Oxide.

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3 years ago
A patient had for dinner a 3 oz steak, 3 oz salmon, 1 medium apple, and 1 cup of nonfat milk. Using the
Llana [10]

Answer:

1

Explanation:

because there barely eating and there eating protien and healthy foods

3 0
3 years ago
Is this correct im so confused.
inysia [295]

Answer:

<em>the last option!!!!</em>

Explanation:

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4 0
3 years ago
A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v
Charra [1.4K]

Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.

Patm = Pwater + PH₂

PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

0.9762bar.\frac{1atm}{1.013bar} =0.9637atm

The absolute temperature is:

K = °C + 273 = 25°C + 273 = 298 K

We can calculate the moles of H₂ using the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.9637atm \times 0.249L }{(0.08206atm.L/mol.K)\times298K} =9.81 \times 10^{-3} mol

Let's consider the following balanced equation.

M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)

The molar ratio of M:H₂ is 1:1. So, 9.81  × 10⁻³ moles of M reacted. The molar mass of the metal is:

\frac{0.539g}{9.81 \times 10^{-3} mol} =54.9g/mol

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3 years ago
Is anyone else's brainly not working or is mine the only one that is tweaking?
omeli [17]
Mine tweaking as well
5 0
3 years ago
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