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2 years ago

A lock consist of 4 dials, where each dial has 6 letters.what is the probability of guessing the right combination in one try?

Mathematics

2 answers:

fredd [130]2 years ago

5 0

Answer:

Step-by-step explanation:

The total number of choices is 6 * 6 * 6 * 6 = 1296

You have one chance to get it right

That's 1/1296 = 0.00077

kramer2 years ago

5 0

Answer:

1/1296

Step-by-step explanation:

The probabilty of getting one of the dials correct is 1/6 because there are 6 letters on each dial. So if there are 4 dials, then the chance is multiplied by itself 4 times (1/6 * 1/6 *1/6 * 1/6). 1/6 * 1/6 *1/6 * 1/6 is equal to 1/1296.

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Madison has a collection of 220 coins. How many coins represent 5% of her

ella [17]

Answer:

220/x=100/5

(220/x)*x=(100/5)*x - we multiply both sides of the equation by x

220=20*x - we divide both sides of the equation by (20) to get x

220/20=x

11=x

x=11.

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3 years ago

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Ket [755]

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3 years ago

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5x^2-2x=2<br>help plsmmm

Yuki888 [10]

Answer:

Presumably you're solving for x here? Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

$5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\$

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

$25x^2 - 10x - 10 = 0\\$

Now we'll add 11 to both sides:

$25x^2 - 10x + 1 = 11\\$

Which makes the left side a perfect square:

$(5x - 1)^2 = 11$

And now we can solve for x:

$(5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}$

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

$x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86$ $x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46$