What is 56x13+15.... will mark brainliest whoever answers correctly the first time
1 answer:
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Answer:
Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) =
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) =
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
segment AB over segment A double prime B double prime = the square root of 13 over 2 times the square root of 13
Step-by-step explanation:
Triangle ABC has vertices at points A(-3,3), B(1,-3) and C(-3,-3).
1. Reflection over x = 1 maps vertices A, B and C as follows
- A(-3,3)→A'(5,3);
- B(1,-3)→B'(1,3);
- C(-3,-3)→C'(5,-3).
2. Dilation by a scale factor of 2 from the origin has the rule
(x,y)→(2x,2y)
So,
- A'(5,3)→A''(10,6);
- B'(1,3)→B''(2,6);
- C'(5,-3)→C''(10,-6)
See attached diagram for details
Note that
so
