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denis-greek [22]
4 years ago
11

The proper name for a carbohydrate polymer with 2 subunits is

Chemistry
1 answer:
valentina_108 [34]4 years ago
8 0
Carbohydrates are classified in three major categories depending upon the number of sub units joining to form them. These are,

                                                Monosaccharides

                                                Oligosaccharides

                                                Polysachharides

The simplest single units are monosaccharides, if units are ranging between two and twenty they are called oligosaccharides and above twenty joining units they are called polysachharides.

Result:
          <span>The proper name for a carbohydrate polymer with 2 subunits is called Oligosachharide in general and Disaccharide in specific.</span>
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Explain how you would determine the amount of g in 1.7 mol of Al(OH)2 and give your answer.
krok68 [10]

Answer:

103.7 grams

Explanation:

Al(OH)_{2}

Al: 1 * 26.98 = 26.98

O: 2 * 16.00 = 32.00

H: 2 * 1.01 = 2.02

26.98 + 32.00 + 2.02 = 61.00

\frac{1.7mol}{1} * \frac{61.00g}{1mol} = 103.7 grams of Al(OH)_{2}

6 0
3 years ago
In an unconformity between two layers of rock, how is the upper layer usually described?
weeeeeb [17]
The answer is the first one!!! have a WONDERFUL day!!
3 0
3 years ago
Read 2 more answers
Determine the molarity and mole fraction of a 1.09 m solution of acetone (CH3COCH3) dissolved in ethanol (C2H5OH). (Density of a
Juli2301 [7.4K]

Answer:

Molarity = 0.809 M

mole fraction = 0.047

Explanation:

The complete question is

Calculate the molarity and mole fraction of acetone in a 1.09-molal solution of acetone (CH3COCH3) in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.

Solution -

Solution for molarity:

1.09-molal means 1.09 moles of acetone in 1.00 kilogram of ethanol.

1)  

Mass of 1.09 mole of acetone

= 1.09  mol x 58.0794 g/mol = 63.306 g

Density of acetone = 0.788 g/cm3  

Thus, volume of 1.09 moles of acetone = 63.306 g/0.788 g/cm3 = 80.34 cm3

For ethanol

1000 g divided by 0.789 g/cm3 = 1267.427 cm3

Total volume of the solution = Volume of acetone + Volume of ethanol = 80.34 cm3 + 1267.427 cm3 = 1347.765 cm3  = 1.347 L

a) Molarity:

1.09 mol / 1.347 L = 0.809 M

Mole Fraction  

a) moles of ethanol:

1000 g / 46.0684 g/mol = 21.71 mol

b) moles of acetone:

1.09 / (1.09 + 21.71) = 0.047

3 0
3 years ago
1) Given 1469 of H₂SO4 how<br> many moles do you have
mart [117]

Answer:

15moles

Explanation:

Given parameters:

Mass of H₂SO₄   = 1469g

Unknown:

Number of moles  = ?

Solution:

To solve this problem, let us first find the molar mass of the given compound;

  molar mass = 2(1) + 32 + 4(16)  = 98g/mol

So;

 Number of moles = \frac{mass}{molar mass}    = \frac{1469}{98}  

 Number of moles  = 15moles

4 0
3 years ago
A container of compressed hydrogen with a fixed volume has a pressure of 13.0 atm at a temperature of 20.0 °C. If its temperatur
nevsk [136]

Answer:

P₂ = 16.6 atm

Explanation:

Given data:

Initial pressure = 13.0 atm

Initial temperature = 20.0°C (20+273 = 293 K)

Final temperature = 102.0°C (102+273 =375 K)

Final pressure = ?

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

13.0 atm / 293 K =  P₂/375 K

P₂ = 13.0 atm × 375 K / 293 K

P₂ = 4875 atm. K /293 K

P₂ = 16.6 atm

8 0
3 years ago
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