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miv72 [106K]
3 years ago
5

9. What is the process of nuclear fusion? *

Chemistry
1 answer:
Pavlova-9 [17]3 years ago
5 0

Answer:

the process of carrying light

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Which of the following choices has the compounds correctly arranged in order of increasing solubility in water? (least soluble t
larisa86 [58]

Answer: Option (d) is the correct answer.

Explanation:

As it is known that like dissolves like. So, water being a polar compound is able to dissolve only polar compounds.

Hence, a compound that is ionic or polar in nature will readily dissolve in water. Whereas non-polar compounds will be insoluble in water.

As CCl_{4} is a non-polar compound. Hence, it is insoluble in water.

On the other hand, CHCl_{3} is a polar compound due to difference in electronegativity of chlorine and carbon atom there will be development of partial charges. Hence, there will be dipole-dipole forces existing between them.

Whereas NaNO_{3} is an ionic compound and it will readily dissociate into ions when dissolved in water. Also, there will be ion-dipole interactions between sodium and nitrate ions.

Hence, NaNO_{3} will readily dissolve in water.

Thus, we can conclude that the compounds correctly arranged in order of increasing solubility in water are CCl_{4} < CHCl_{3} < NaNO_{3}.

6 0
3 years ago
What volume (L) of 0.250 M HNO3 is required to neutralize a solution prepared by dissolving 17.5 g of NaOH in 350 mL of water ?
IRINA_888 [86]
<h3>Answer:</h3>

1.75 L HNO₃

<h3>Explanation:</h3>

We are given;

Molarity of HNO₃ as 0.250 M

Mass of NaOH as 17.5 g

Volume of NaOH = 350 mL

We are required to calculate the volume of 0.250 M

We are going to first write the balanced reaction:

NaOH(aq) + HNO₃(aq) → NaNO₃(aq) + H₂O(l)

Then, we calculate the number of moles of NaOH

Moles = Mass ÷ Molar mass

Molar mass of NaOH = 39.997 g/mol

          = 17.5 g ÷ 39.997 g/mol

          = 0.4375 moles

We can now calculate the number of moles of HNO₃ using the mole ratio from the equation;

Mole ratio of NaOH to HNO₃ is 1 : 1

Therefore, if moles of NaOH are 0.4375 moles then;

Moles of HNO₃ will also be 0.4375 moles

We can now calculate the volume of HNO₃

Morality = Number of moles ÷ Volume

Thus;

Volume = Number of moles ÷ Molarity

             = 0.4375 moles ÷ 0.250 M

             = 1.75 L

Therefore, the volume of HNO₃ is 1.75 L

5 0
3 years ago
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