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andrew-mc [135]
3 years ago
12

Calculate the molar mass CaCl2 Ca(NO3)2 Ca(OH)2 CaSO4 BaCl2

Chemistry
2 answers:
irina [24]3 years ago
7 0
On the periodic table it shows the molecular weight of all the elements and what you do is add all the numbers together:
CaCl2=40.08+35.45x2=110.98g/mol
*Ca(NO3)2=40.08+14.01x2+16x6=164.1g/mol
*Ca(OH)2=40.08+16x2+1.008x2=74.096g/mol
CaSO4=40.08+32.06+16x4=136.14g/mol
BaCl2=137.33+35.45x2=208.23g/mol
*these 2 require you to distribute the 2 into each of the elements.
poizon [28]3 years ago
3 0

Answer:0.0008 mmg

Explanation:

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pashok25 [27]

Answer:

HgSO₄

Explanation:

% => g => moles => ratio => reduce => empirical ratio

%Hg = 67.6% => 67.6g/201g/mol = 0.34mol

%S    = 10.8% => 10.8g/32g/mol = 0.34mol

%O   = 21.6% => 21.6g/16g/mol = 1.35mol

Hg:S:O => 0.34:0.34:1.35

Reduce to whole number ratio by dividing by the smaller mole value...

Hg:S:O => 0.34/.34:0.34/.34:1.35/.34 => Empirical Ratio = 1:1:4

∴ Empirical Formula is HgSO₄

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3 years ago
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amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

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