Help me solve this equation for K please, will give brainliest

HELPPP!!! In reaction 2Sr+O2=2SrO how many moles of Oxygen will be needed to react with 36.9g of SrO?

Step2247 [10]

6000 I pretty sure tell me if it's right

6 0

2 years ago

A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?

Katen [24]

Answer:

T2 = 260 K

Explanation:

Given data:

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K

V1 = 1.75 L

P2 = 210.0 kPa

V2 = 1.30 L

To find:

T2 = ?

Formula:

$\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$

$T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}$

Calculation:

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K

8 0

3 years ago

Select the pair that consists of a base and its conjugate acid in that order. CO32−/CO22−

lana [24]

Answer: The pair that consists of a base and its conjugate acid in that order. $NH_3/NH_4^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

$H_3PO_4\rightarrow H_PO_4{2^-}+2H^+$

$H_2CO_3\rightarrow HCO_3^-+H^+$

$NH_3+H^+\rightarrow NH_4^+$

$HCO_3^-\rightarrow CO_3^{2-}+H^+$

$NH_3$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $NH_4^+$ which is a conjugate acid.

3 0

3 years ago

Consider the following four structures: What is the relationship of I and II? What is the relationship of I and III? What is the

daser333 [38]

Answer:

The different structures are shown in the attachment.

I and II - structural isomers

I and III - Structural isomers

I and IV - structural isomers

II and III - structural isomers

II and IV - structural isomers

III and IV - stereoisomers

Explanation:

The knowledge of Isomerism is tested here; there are two types of isomerism ; structural and stereoisomerism.

Structural Isomers have similar molecular and different double bond positioning, these occurs mostly in ALKENE FAMILY.

Stereo-isomers have the same molecular formular and similar patterns but differ in their spatial arrangement. trans and cis are typical examples of stereo-isomers.

From the question; Relationship between I and II is that they are structural isomers since they have the same molecular formula, but different bond atom arrangement and infact they are the same compound.

Relationship between I and III is that they are structural isomers with similar molecular formular but differ in the double bond position.

Relationship between I and IV is that they are structural isomers with similar molecular formula but different double bond arrangement.

Relationship between II and III is that they are structural isomers with similar molecular formular but different double bond position

Relationship between II and IV is that they are also structural isomers with the same molecular formular but different double bond position.

Relationship between III and IV is that they are stereo-isomers with same molecular formula but different spatial arrangement, hence cis and trans.

4 0

3 years ago

Pls somebody help me with this question! The pictures have to be in order!

irina1246 [14]

Answer:

I believe the organelle should replace the question mark!

3 0

2 years ago

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