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Ira Lisetskai [31]
4 years ago
8

1. The basic building block of matter are atoms. Every atom is basically a tiny sphere. Every atom is composed of 2 regions, the

outer part of the sphere is called the _______ and accounts for about 99.95% of the volume of an atom. 2. The electron cloud is the region of an atom in which the __________ are found. __________ are tiny particles with a -1 electrical charge and almost no mass. Electricity is _________ flowing though a conductor, usually metal. 3. Every atom is composed of 2 regions. The very tiny center part of the spherical atom is called the _____________. The __________ accounts for about 99.95% of the mass of the atom even though it has almost no volume. 4. Every atom has a nucleus. The nucleus contains 2 different types of particles. The particle with the +1 electrical charge is called the __________. It has almost 2000 times more mass than an electron. The number of __________ in the nucleus determine how many electrons the neutral atom has and all of the chemical reactions the atom can do. 5. Every atom has a nucleus. The nucleus contains 2 different types of particles. The particle with no (0) electrical charge is called the __________. This particle is electrically neutral. The +1 charged protons would repel each other and destroy the nucleus if the _______________ were not neutralizing the repulsive force between the protons. 6. When graphing how the experimental “effect” depends on the experimental “cause”, the graph can show either a _______________ or an inverse relationship or no relationship. If the “effect” (dependent variable) value increases when we make the “cause” (independent variable) value increase, then we call this a ____________________. 7. When graphing how the experimental “effect” depends on the experimental “cause”, the graph can show either a direct relationship or an ______________ or no relationship. If the “effect” (dependent variable) value decreases when we make the “cause” (independent variable) value increase, then we call this an ____________________. 8. When graphing how the experimental “effect” depends on the experimental “cause”, the graph can show either a direct relationship or an inverse relationship or _____________. If the “effect” (dependent variable) value doesn’t change when we make the “cause” (independent variable) value increase, then we call this ____________________. 9. An experiment needs an _________________ to validate its results. The ________________ can be one of 2 things. The __________________ can be a set of experimental conditions we repeat several times throughout the experiment. Or the ________________ can be a set of conditions which other experimenters have used and is considered “normal” or “state of the art.” 10. A variable is something which can change during an experiment. It works best when we only let 2 variables change. All the rest are kept constant and are called _______________. fill in the blanks with these words. Direct relationship ,No relationship ,Proton(s), Neutron(s), Controlled variable(s), Electron(s), Experimental control, Inverse relationship, Electron cloud, Nucleus.
Physics
1 answer:
Bogdan [553]4 years ago
6 0

The answers would be:

1. Electron cloud

2. Electrons, Electrons, Electrons

3. Nucleus, nucleus

4. Protons, protons

5. Neutrons, Neutrons

6. Direct, direct.

7. Inverse, inverse

8. No relationship, no relationship

9. Experimental control

10. Controlled variables

Here is more about the question:

An atom has 3 subatomic particles:

Proton: positively charged particles

Electron: Negatively charged particles

Neutrons: Neutrally charged particles

The nucleus is made up of the protons and neutrons, while the electrons are found outside, within the electron cloud.

Electrons are very important in bonding. It is also heavily involved in electricity. Electricity is the flow of electrons through a conductor.

Relationships in a graph:

For direct relationships, you just need to remember, when one goes up, the other one goes up too.

Inverse relationships on the other hand, when one goes up the other goes down.

If no change occurs, then we can say that there is no relationship.

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3. Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius
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(a) The initial speed must the object be launched so that it reaches

the surface of Planet 2 with zero speed is  √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) An inequality between M₁ and M₂ that represents when (a)

can occur is { M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

(c)  if R₁ = R₂, then M₁ must be greater than M₂ is proved.

<h3>What is gravity?</h3>

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given, Planet 1 has mass M₁ and radius R₁. Planet 2 has mass M₂ and radius R₂. The two planets are a distance of L apart, measured from surface to surface. An object is launched with some initial speed from the surface of Planet 1 directly towards Planet 2. For this problem, assume that Planets1 and 2 are stationary.

If v is the launch velocity, then initial total energy will be

T.E  = 1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L)

The final total energy will be

T.E  =0 + ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

From energy conservation principle, we get

1/2 mv² + ( -GM₁m/ R₁ - G M₂m/(R₂ + L) = ( -GM₁m/ (R₁ +L) - G M₂m/ R₂)

v = √[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}]

(b) an inequality between M₁ and M₂  so that object reaches the surface of Planet 2 with zero speed is

[2G{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂}] =0

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

Thus, this is an inequality between M₁ and M₂.

(c) If R₁ = R₂, then

{ M₁/ R₁ + M₂/(R₂ + L) - M₁/ (R₁ +L) - M₂/ R₂} ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L) / R (R+L)   ≥ 0

M₁(R+L) + M₂R - M₁R  -M₂(R+L)  ≥ 0

M₁L - M₂L  ≥ 0

M₁ ≥ M₂

M₁ must be greater than M₂.

Learn more about gravity.

brainly.com/question/4014727

#SPJ1

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Given a 45 45 90 prism with index of 1.5, immersed in air. The hypotenuse acts as the reflecting face by TIR. A ray of light ent
Genrish500 [490]

Answer:

83.6°

Explanation:

For the ray to be totally internally reflected, at the boundary, the angle of refraction is 90. Using the law of refraction where

n₁sinθ₁ = n₂sinθ₂ where n₁ = refractive index of prism = 1.5, θ₁ = critical angle in prism, n₂ = refractive index of air = 1 and θ₂ = refractive angle = 90°.

So, substituting these values into the equation,

n₁sinθ₁ = n₂sinθ₂

1.5 × sinθ₁ = 1 × sin90

1.5 × sinθ₁  = 1

sinθ₁ = 1/1.5

sinθ₁ = 0.6667

θ₁  = sin*(0.6667)

θ₁  = 41.8°

So, for total internal reflection, an incidence angle of 41.8° is required. So, a full convergence angle of 2 × 41.8° = 83.6° is required for the whole bundle of rays.

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